CODEWITHSUNDEEP
c++structsizeof
kiokko89
kiokko89

Reputation: 211

Understanding C++ struct size

Consider the following code:

struct CExample  {
    int a; 
}            

int main(int argc, char* argv[]) {  

    CExample ce1;  
    CExample ce2;  

    cout << "Size:" << sizeof(ce1) << " Address: " << &ce1 << endl;   
    cout << "Size:" << sizeof(ce2) << " Address: " << &ce2 << endl;   

    CExample ceArr[2];
    cout << "Size:" << sizeof(ceArr[0])<< " Address: "<< &ceArr[0] <<endl;
    cout << "Size:" << sizeof(ceArr[1])<< " Address: "<< &ceArr[1] <<endl;

    return 0;
}

Output example:
ce1: Size=4, Address: 0039FAA0
ce2: Size=4, Address: 0039FA94
ceArr[0]: Size=4, Address: 0039FA84
ceArr[1]: Size=4, Address: 0039FA88

With the code there is a 12-byte between the addresses of the first two objects (ce1 and ce2) but there is only a 4-byte difference between the objects in the array.

I thought data-alignment would have something to do with the issue, but I'm still stumped. Any idea what is actually going on here?

Upvotes: 7

Views: 2617

Answers (4)

Johan Kotlinski
Johan Kotlinski

Reputation: 25769

The compiler does not only use the stack for keeping your local variables - it also uses it for example for argument passing, and some of the overhead caused by std::cout. That's probably what the extra space between your variables is used for.

If you instead make your variables static, like this:

static CExample ce;
static CExample ce2;

static CExample ceArr[2];

...the variables will be placed in BSS memory instead, and the alignment will more likely be what you expect.

The reason why arrays are packed, and individual items are not, is clarified by other answers...

Upvotes: 1

Benjamin Lindley
Benjamin Lindley

Reputation: 103751

Because objects in an array are required to be contiguous. Objects declared consecutively on the stack(in source code, not machine) are not[required to be contiguous], although they can be.

Upvotes: 15

EmeryBerger
EmeryBerger

Reputation: 3975

The reason is that, on most architectures, unaligned loads are slow. See the Wikipedia entry on data structure alignment for a good explanation. The compiler places each one of your data structures at the start of a data word. However, in arrays, the items are placed contiguously in memory (as the C++ standard requires).

Upvotes: 0

Billy ONeal
Billy ONeal

Reputation: 106609

The standard says nothing about this. The compiler is free to insert whatever padding it wants between the items.

(If I had to guess, I'd guess that your compiler implements some form of stack protection/canary in debug mode (and that you are compiling in debug mode))

Upvotes: 6

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