Reputation: 3443
for the line
Tester[0]/Test[4]/testId
Tester[0]/Test[4]/testId
Test[1]/Test[4]/testId
Test[2]/Test[4]/testId
I want to match the first part of the path including the first [, n and ] and first / so for line above I would get
Tester[0]
Tester[0]
Test[1]
Test[2]
I have tried using
var rx = new Regex(@"^\[.*\]\/");
var res = rx.Replace("Tester[0]/Test[4]/testId", "", 1 /*only one occurrence */);
i get
res == "testId";
rather than
res == "Test[4]/testId"
which is what im hoping for so its matching the first open square bracket and the last closing bracket. I need it to match only the first closing bracket
Update: Sorry, i am trying to match the first forward slash also.
Tester[0]/
Tester[0]/
Test[1]/
Test[2]/
Solution: to remove the first match using "?":
var rx = new Regex(@"^.*?\[.*?\]\/");
var res = rx.Replace("Tester[0]/Test[4]/testId", "", 1 /*only one occurrence */);
Upvotes: 1
Views: 536
Reputation: 749
Is this the sort of thing you are looking for?
updated
var str="Tester[0]/Test[4]/testId\nTester[0]/Test[4]/testId\nTest[1]/Test[4]/testId\nTest[2]/Test[4]/testId"
console.log(str)
// Tester[0]/Test[4]/testId
// Tester[0]/Test[4]/testId
// Test[1]/Test[4]/testId
// Test[2]/Test[4]/testId
var str2=str.replace(/\/.+/mg,"")
console.log(str2)
// Tester[0]
// Tester[0]
// Test[1]
// Test[2]
this works by starting the match at the first '/' and then ending when the line ends and replaces this match with " ". the m flags multi-line and the g flags to do a global match.
Upvotes: 0
Reputation: 16310
You can use lookahead
and lookbehind
approach to find matching and replace accordingly :
With lookaround
approach, your regex would be like this :
(?=/).*(?<=])
Upvotes: 0
Reputation: 16817
I'm assuming this was your original regex pattern: ^.*\[.*\]/
(the pattern in your question does not match the lines).
This pattern uses greedy quantifiers (*
), so, even though we only requested one match, the pattern itself matches more than we'd like. As you noticed, it matched until the second occurrence of the square brackets.
We can make this pattern non-greedy by adding question marks to the quantifiers: ^.*?\[.*?\]/
.
Although this works for your use-case, a better pattern may be: ^[^/]+/
. This removes any character up to the first forward-slash. The [^ ... ]
is a negative character class (the brackets are unrelated to the brackets in the strings we're matching against). In this case, it matches any character that isn't a forward-slash.
For this simple text manipulation, though, we could just use a String.Substring()
instead of regular expressions:
line.Substring(line.IndexOf('/') + 1);
This is faster and easier to understand than a regular expression pattern.
Upvotes: 1