CODEWITHSUNDEEP
python-2.7dictionary
Eric
Eric

Reputation: 29

Python: Sort dict of lists by element

I created a dict of lists as such.

{'chans': [['24', 'X', 'RCP', '8400.0', 'mex', '325.0K', '8', '50 1', '17', 266, **datetime.time(22, 0)**, '17', 266, datetime.time(23, 0), '00', '23', '00', 20.604799168660975, '041'], 
 ['24', 'X', 'RCP', '8400.0', 'ody', '325.0K', '4', '40 1', '17', 266, **datetime.time(17, 0)**, '17', 266, datetime.time(18, 0), '00', '18', '00', 16.31949387241184, '053'], 
 ['24', 'X', 'RCP', '8400.0', 'mro', '325.0K', '8', '50 1', '17', 266, **datetime.time(18, 0)**, '17', 266, datetime.time(19, 0), '00', '19', '00', 27.872042154574956, '074']]}

I need to sort this in ascending order by using the date time object (element 10 in each list). I'm stuck at determining the proper key/value. In essence, I'm not sure what to do.

Upvotes: 0

Views: 775

Answers (2)

khelili miliana
khelili miliana

Reputation: 3822

You can use itemgetter, and just select the index of the item in the list not dict, we can't order a dictionnary,

from operator import itemgetter
import datetime

f = {'chans': [['24', 'X', 'RCP', '8400.0', 'mex', '325.0K', '8', '50 1', '17', 266, """datetime.time(22, 0)""", '17', 266, datetime.time(23, 0), '00', '23', '00', 20.604799168660975, '041'], 
 ['24', 'X', 'RCP', '8400.0', 'ody', '325.0K', '4', '40 1', '17', 266, """datetime.time(17, 0)""", '17', 266, datetime.time(18, 0), '00', '18', '00', 16.31949387241184, '053'], 
 ['24', 'X', 'RCP', '8400.0', 'mro', '325.0K', '8', '50 1', '17', 266, """datetime.time(18, 0)""", '17', 266, datetime.time(19, 0), '00', '19', '00', 27.872042154574956, '074']]}

sorted(f['chans'], key=itemgetter(10))

Upvotes: 1

hyperneutrino
hyperneutrino

Reputation: 5425

sort function

There is a sort function (in-place) and a sorted function (returns list sorted). Each of these takes an optional argument called key, which is called on each element for comparison. In your case, you want to call sort(dictionary["chans"]), which will sort the lists. Since you want to sort by the 11th element in each list, you would do this:

sort(dictionary["chans"], key = lambda sublist: sublist[10])

The key takes a sublist and returns its 11th element, so sort is sorting the sublists by their 11th elements (the datetime).

You can make key whatever you want to suit your needs.

Upvotes: 0

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