CODEWITHSUNDEEP
pythondjangodjango-models
Atma
Atma

Reputation: 29805

use unique id in django model custom save

I am trying to create unique slugs from persons names, which will have obvious duplicates. My idea is to add the id to the slug as a unique identifier. The problem is that the unique id is not generated until the save completes.

This is what I tried:

def save(self, *args, **kwargs):

        if getattr(self, 'name', True):

            if not self.pk:
                matching_slugs = Entity.objects.filter(slug=slugify(self.name))
                print matching_slugs
                if len(matching_slugs) > 0:
                    self.slug=slugify(self.name+' temp')
                elif len(matching_slugs) == 0:
                    self.slug=slugify(self.name)
        super(Entity, self).save(*args, **kwargs)
        self.slug=slugify(self.name+' '+str(self.id))
        self.save()

I get the error:

maximum recursion depth exceeded in cmp

I'm thinking this is not the best way to do this.

How can I make names unique on save?

Upvotes: 2

Views: 708

Answers (2)

Atma
Atma

Reputation: 29805

I changed the save() to be:

    super(Entity, self).save(*args, **kwargs)
    self.slug=slugify(self.name+' '+str(self.id))
    super(Entity, self).save(*args, **kwargs)

Upvotes: 0

user8060120
user8060120

Reputation:

May be you can use simple construction?:

import uuid


def save(self, *args, **kwargs):
    if not self.slug:
          self.slug = "%s.%s" % (self.name , uuid.uuid4())
    super(Entity, self).save(*args, **kwargs)

Upvotes: 3

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