Reputation: 2653
char* str =
"\
a-a-a-a\
differing the text, because that was the lecture thing\
the text has been changed\
I know!\
the text has been changed\
";
i deeply thinking about this for hours but can`t figure it out.. with using only stdio.h
string.h is not allowed, but using only basic things..
how can I get string length? someone please help me.
the goal is to find frequency of input pattern in a given string
ex) ha => 2, di => 1..
help me.
Upvotes: 2
Views: 2960
Reputation: 2658
This works for some test input string, but i higly recommend to check it with more cases.
Suppose we have implemented strstr()
.
strstr()
Is a C library function from string.h
Library
char *strstr(const char *haystack, const char *needle)
This function finds the first occurrence of the substring needle
in the source string haystack
.
The terminating \0
characters are not compared.
source: TutorialsPoint (with some edition)
Code
#include <stdio.h>
#include <string.h>
unsigned int Neostrlen(const char* str)
{
unsigned int length = 0;
while (*str != 0)
{
str++;
length++;
}
return length;
}
int BluePIXYstrlen(char* str)
{
int len = 0;
sscanf(str, "%*[^0]%n", &len);
return len;
}
int Jeanfransvastrlen(char* str)
{
int i;
for (i=0;str[i];i++);
return i;
}
int main(int argc, char **argv){
//is it true, no need to malloc????
char* str =
"\
P-P-A-P\
I have a pen, I have a apple\
Uh! Apple-Pen!\
I have a pen, I have pineapple\
Uh! Pineapple-Pen!\
Apple-Pen, Pineapple-Pen\
Uh! Pen-Pineapple-Apple-Pen\
Pen-Pineapple-Apple-Pen\
";
printf("len: %d\n", Jeanfransvastrlen(str));
printf("len: %d\n", Neostrlen(str));
printf("len: %d\n", BluePIXYstrlen(str));
printf("sss:%s\n\n\n", str);
char * search = "have";//search for this substring
int lenSr= Neostrlen(search);
printf("lenSr: %d\n", lenSr);
char * ret;
ret = strstr(str, search);
int count = 0;
while (ret){
//printf("The substring is: %s\n\n\n\n", ret);
count++;
for (int i=0;i<lenSr;i++){
printf("%c", ret[i]);
}
printf("\nEnd sub\n");
for (int i=0;i<lenSr;i++){
ret++;
}
ret = strstr(ret, search);
}
printf("count: %d\n", count);
return 0;
}
Edited
For only using stdio.h
you can substitute all strstr()
with this version of mystrstr()
adopted from leetcode
mystrstr()
char* mystrstr(char *str, const char *target) {
if (!*target) {
return str;
}
char *p1 = (char*)str;
while (*p1) {
char *p1Begin = p1, *p2 = (char*)target;
while (*p1 && *p2 && *p1 == *p2) {
p1++;
p2++;
}
if (!*p2){
return p1Begin;
}
p1 = p1Begin + 1;
}
return NULL;
}
Hint
I removed const
from first first argument of mystrstr()
because of I want to change it later, and this is the only changed i have made on original code.
This version is sensitive to Uppercase and lowercase letters in string,
for example Apple
is differ from apple
.
As chux said in comments my code return substrings of "ababa"
from source
"aba"
only {aba}
not more. and this is because i change string pointer inside while
in last for
.
Suggestion
Try to implement your version of strstr()
, and strlen()
Upvotes: 0
Reputation: 3786
As for length of string, the implementation of strlen
isn't very complicated.
All you should do is to loop over the string until you find a \0
(end of string) and count the number of times you looped.
unsigned int mystrlen(const char* str)
{
unsigned int length = 0;
while (*str != 0)
{
str++;
length++;
}
return length;
}
This could be shortened into
unsigned int len = 0;
for (; str[len]; len++);
Upvotes: 5
Reputation: 12321
A string in pure C is just a pointer to a memory. IF the last element is 0, then you can use strlen or whatever checks for that. But if that is not the case you need to memorize the length in a variable.
So if it is 0-terminated just loop to the first element that is 0 (not '0') and thats the end. If you counted the elements you have the string-length.
Upvotes: 0