CODEWITHSUNDEEP
powershell
Andrew Lindeman
Andrew Lindeman

Reputation: 11

PowerShell where object

I'm trying to do something fairly simple - I have a string array with multiple elements. I want to create another string array with the elements that don't contain a certain substring.

Unfortunately using both -notlike and -notcontains, my $l returns no entries. I expect it to return one entry with "two" in it. I suspect I'm doing something simple wrong, but I haven't been able to figure it out.

$s = "one","two"

Write-Host "s:"

Write-Host "$s"

I have tried both -notlike and -notcontains and both return $l as empty. I am NOT using both at the same time.

#$l = Where-Object ($s -notlike "on")

$l = Where-Object ($s -notcontains "on")

Write-Host "l:"

Write-Host "$l"

Again, I am wanting $l to return with one element "two" since "on" is matched in "one".

Upvotes: 1

Views: 444

Answers (2)

mjolinor
mjolinor

Reputation: 68243

@Mark Wragg's comments and answer are spot on with regard to the wildcard syntax required for the -notlike operator.

Beyond that, the Where-Object clause isn't necessary at all, since the comparison operators will also operate as filters when used against an array:

$s = "one","two"
"s: $s"

$l = $s -notlike "on*"
"l: $l"

Upvotes: 3

Mark Wragg
Mark Wragg

Reputation: 23355

-NotLike will work, but you need to use curly braces around your expression in the Where-Object (you are currently using brackets) and you need to use a * as a wildcard character.

In the Where-Object you also need to use $_ as your variable. This is a special automatic variable that represents the current item in the pipeline as it is being processed (for example, "one", then "two"):

$s = "one","two"
"s: $s"

$l = $s | Where-Object { $_ -notlike "on*"}
"l: $l"

Upvotes: 4

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