CODEWITHSUNDEEP
javascriptphpjqueryajaxw3c-geolocation
Valentin M
Valentin M

Reputation: 61

Cannot pass JS variable to PHP using AJAX

I am trying to get current location of user.

I have JS script to get current Latitude and Longitude with AJAX to send js variables to index.php.

$(document).ready(function() {
if ("geolocation" in navigator){
    navigator.geolocation.getCurrentPosition(function(position){
            var userLat = position.coords.latitude;
            var userLong = position.coords.longitude;
            console.log(userLong);
            console.log(userLat);

            $.ajax({
              type: 'POST',
              url: 'index.php',
              data: {
              userLat : userLat,
              userLong : userLong
              },
              success: function(data)
                {
                  console.log(data);

                }

            });

    });
}else{
    console.log("Browser doesn't support geolocation!");
}});

Then I am trying to do this in my index.php:

echo $_POST['userLat'];
echo $_POST['userLong'];

Nothing shows up. Thanks in advance.

Upvotes: 0

Views: 919

Answers (2)

Mohammed Elhag
Mohammed Elhag

Reputation: 4302

Nothing shows up.

And that's correct you will never get any thing by browsing index.php because there is no POST at this time , AJAX is internal and the only way to show a result from index.php is in the page that you send from it an ajax call.

At this :

success: function(data)
            {
              console.log(data);

            }

you could control where to show your data that comes from index.php by , for example alert(data) or document.getElementById("someelement").innerHTML=data; and so on.

Upvotes: 1

DFriend
DFriend

Reputation: 8964

It might help to define and return a dataType for the ajax.

add this to your list of ajax options

 dataType: 'json',

Then in index.php encode and echo a json string. Remove the lines

echo $_POST['userLat'];
echo $_POST['userLong'];

replace them with

echo json_encode($_POST);

The console.log(data); in the success function should show an object with two items: 'userlat' and 'userLong' and associated values for each. Or it should if $_POST had those two items.

If you want the browser screen to update you will have to take data and use it to modify the DOM.

Upvotes: 1

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