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SugarMouse
SugarMouse

Reputation: 203

Is there a good way to alter execution order of child processes created with fork()?

I am looking for creating child processes for which I can control their order of processing.

Simple example:

Because of the fact that we can't know for sure which process will be executed first, there are high chances that the final result would be:

Message 2

Message 1

End

I am trying to make sure that the second child executes the print before the first child and that the parent executes its print after all the children.

For the parent it's quite easy with the wait()/waitpid() functions. However it seems harder with the children.

Here is an implementation of my ideas to achieve the objective:

(note: I'm still quite new to the creation of child processes and I may have misunderstood things in this implementation)

#include <stdlib.h>
#include <stdio.h>

#include <sys/types.h>
#include <signal.h>
#include <unistd.h>

static int init = 0;

void setInitFinished(int sig)
{
    if (sig == SIGUSR1)
        init = 1;
}

int main()
{
    signal(SIGUSR1, setInitFinished);
    
    pid_t pid1, pid2;
    int status1, status2;
    
    // CHILD 1
    if (!(pid1 = fork()))
    {
        while (!init); // Waiting all children to be initiated

        // Once all children created, we wait for child 2 to print its message
        int pidOfChild2 = getpid()+1; // I checked, the PID is correct
        waitpid(pidOfChild2, &status1, 0);
        
        printf("MESSAGE 2\n");
        exit(0);
    }
    
    // CHILD 2
    if (!(pid2 = fork()))
    {
        while (!init); // Waiting all children to be initiated
        
        // No need to wait since it's the first message to be printed
        printf("MESSAGE 1\n");
        exit(0);
    }
    
    // PARENT

    // All children have been created, tell it to all the children
    kill(pid2,SIGUSR1);
    kill(pid1,SIGUSR1);
    
    // When every child has finished its work, continue parent process
    waitpid(pid1, &status1, 0);
    waitpid(pid2, &status2, 0);
    
    printf("Parent end\n");
    
    return 0;
}

In the child 1 I am trying to wait for the Child 2 with waitpid(pidOfChild2, ...); but it doesn't seem to work.

I'm still discovering the fork functionalities so I'm pretty sure to misunderstand a lot of things here.

NB: I want to avoid using sleep(), it could work but it's not pretty

Upvotes: 1

Views: 680

Answers (1)

unwind
unwind

Reputation: 399881

You need to use actual inter-process communication to achieve this.

You seem to think that the waitpid() function has something to do with waiting for a process to print output, but that's not at all what it does.

Create a semaphore in the parent, pass it to both children, and have one child wait on the semaphore before printing and the other one messaging the semaphore after it's done printing.

Upvotes: 2

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