Reputation: 6364
How to use mongodb java driver to compare dayOfYear of two ISODate objects?
Here are my docs
{"name": "hello", "count": 4, "TIMESTAMP": ISODate("2017-10-02T02:00:35.098Z")}
{"name": "hello", "count": 5, "TIMESTAMP": ISODate("2017-10-02T02:00:35.098Z")}
{"name": "goodbye", "count": 6, "TIMESTAMP": ISODate("2017-10-01T02:00:35.098Z")}
{"name": "foo", "count": 6, "TIMESTAMP": ISODate("2017-10-02T02:00:35.098Z")}
I want to compare the day in "TIMESTAMP" to perform some aggregation
Bson match = Aggregates.match(eq("name": "hello"));
Bson group = Aggregates.group(new Document("name", "$name"), Accumulators.sum("total", 1));
collection.aggregate(Arrays.asList(match, group))
Now I am not sure how to do this aggregation for all the records that belongs to particular day?
so my expected result for "2017-10-02" is
[{"_id": {"name":"hello"}, "total": 9}, {"_id": {"name":"foo"}, "total": 6}]
Upvotes: 0
Views: 1142
Reputation: 47905
Given the following documents:
{"name": "hello", "count": 4, "TIMESTAMP": ISODate("2017-10-02T02:00:35.098Z")}
{"name": "hello", "count": 5, "TIMESTAMP": ISODate("2017-10-02T02:00:35.098Z")}
{"name": "goodbye", "count": 6, "TIMESTAMP": ISODate("2017-10-01T02:00:35.098Z")}
{"name": "foo", "count": 6, "TIMESTAMP": ISODate("2017-10-02T02:00:35.098Z")}
The following command ...
db.getCollection('dayOfYear').aggregate([
// project dayOfYear as an attribute
{ $project: { name: 1, count: 1, dayOfYear: { $dayOfYear: "$TIMESTAMP" } } },
// match documents with dayOfYear=275
{ $match: { dayOfYear: 275 } },
// sum the count attribute for the selected day and name
{ $group : { _id : { name: "$name" }, total: { $sum: "$count" } } }
])
... will return:
{
"_id" : {
"name" : "foo"
},
"total" : 6
}
{
"_id" : {
"name" : "hello"
},
"total" : 9
}
I think this meets the requirement expressed in your OP.
Here's the same command expressed using the MongoDB Java driver:
MongoCollection<Document> collection = mongoClient.getDatabase("stackoverflow").getCollection("dayOfYear");
Document project = new Document("name", 1)
.append("count", 1)
.append("dayOfYear", new Document("$dayOfYear", "$TIMESTAMP"));
Document dayOfYearMatch = new Document("dayOfYear", 275);
Document grouping = new Document("_id", "$name").append("total", new Document("$sum", "$count"));
AggregateIterable<Document> documents = collection.aggregate(Arrays.asList(
new Document("$project", project),
new Document("$match", dayOfYearMatch),
new Document("$group", grouping)
));
for (Document document : documents) {
logger.info("{}", document.toJson());
}
Update based on this comment:
One of the problems with project is that it only include fields you specify . The above input is just an example. I have 100 fields in my doc I can't sepecify every single one so if I use project I have to specify all 100 fields in addition to "dayOfYear" field. – user1870400 11 mins ago
You can use the following command to return the same output but without a $project
stage:
db.getCollection('dayOfYear').aggregate([
// ignore any documents which do not match dayOfYear=275
{ "$redact": {
"$cond": {
if: { $eq: [ { $dayOfYear: "$TIMESTAMP" }, 275 ] },
"then": "$$KEEP",
"else": "$$PRUNE"
}
}},
// sum the count attribute for the selected day
{ $group : { _id : { name: "$name" }, total: { $sum: "$count" } } }
])
Here's that command in its 'Java form':
MongoCollection<Document> collection = mongoClient.getDatabase("stackoverflow").getCollection("dayOfYear");
Document redact = new Document("$cond", new Document("if", new Document("$eq", Arrays.asList(new Document("$dayOfYear", "$TIMESTAMP"), 275)))
.append("then", "$$KEEP")
.append("else", "$$PRUNE"));
Document grouping = new Document("_id", "$name").append("total", new Document("$sum", "$count"));
AggregateIterable<Document> documents = collection.aggregate(Arrays.asList(
new Document("$redact", redact),
new Document("$group", grouping)
));
for (Document document : documents) {
logger.info("{}", document.toJson());
}
Note: Depending on the size of your collection/your non functional requirements/etc you may want to consider the performance of these solutions and either (a) add a match stage before you start projecting/redacting or (b) extract dayOfYear into its own attribute so that you can avoid this complexity entirely.
Upvotes: 2