Reputation:
I have a dictionary of words with their frequencies as follows.
mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}
I have a set of strings (removed punctuation marks) as follows.
recipes_book = "For todays lesson we will show you how to make biscuit pudding using
yummy tim tam milk and rawsugar"
In the above string I need output only "biscuit pudding", "yummy tim tam" and "milk" by referring the dictionary. NOT sugar, because its rawsugar in the string.
However, the code I am currently using outputs sugar as well.
mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}
recipes_book = "For today's lesson we will show you how to make biscuit pudding using yummy tim tam milk and rawsugar"
searcher = re.compile(r'{}'.format("|".join(mydictionary.keys())), flags=re.I | re.S)
for match in searcher.findall(recipes_book):
print(match)
How to avoid using sub-strings like that and only consider one full tokens such as 'milk'. Please help me.
Upvotes: 2
Views: 58
Reputation: 4196
One more way using re.escape
.
More info regarding re.escape here !!!
import re
mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}
recipes_book = "For today's lesson we will show you how to make biscuit pudding using yummy tim tam milk and rawsugar"
val_list = []
for i in mydictionary.keys():
tmp_list = []
regex_tmp = r'\b'+re.escape(str(i))+r'\b'
tmp_list = re.findall(regex_tmp,recipes_book)
val_list.extend(tmp_list)
print val_list
Output:
"C:\Program Files (x86)\Python27\python.exe" C:/Users/punddin/PycharmProjects/demo/demo.py
['yummy tim tam', 'biscuit pudding', 'milk']
Upvotes: 0
Reputation: 3027
You can update your code with regex word boundary:
mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}
recipes_book = "For today's lesson we will show you how to make biscuit pudding using yummy tim tam milk and rawsugar"
searcher = re.compile(r'{}'.format("|".join(map(lambda x: r'\b{}\b'.format(x), mydictionary.keys()))), flags=re.I | re.S)
for match in searcher.findall(recipes_book):
print(match)
Output:
biscuit pudding
yummy tim tam
milk
Upvotes: 0
Reputation: 5950
Use word boundary '\b'. In simple words
recipes_book = "For todays lesson we will show you how to make biscuit pudding using
yummy tim tam milk and rawsugar"
>>> re.findall(r'(?is)(\bchocolates\b|\bbiscuit pudding\b|\bsugar\b|\byummy tim tam\b|\bmilk\b)',recipes_book)
['biscuit pudding', 'yummy tim tam', 'milk']
Upvotes: 1