CODEWITHSUNDEEP
clinuxgccarchlinux
dems98
dems98

Reputation: 884

GCC 7.2 compiles shared library instead of executable

I have a virtual machine with ArchLinux installed. Here when I compile with GCC by running gcc file.c it gives me a shared library instead of an executable.

Later I find out that the problem is related only to GCC 7.2, in fact, when I compile with GCC 6.4, the output file is an executable.

How do I fix this?

Upvotes: 1

Views: 2075

Answers (2)

oxfist
oxfist

Reputation: 789

To complement the answer that mentioned file as you pointed out in the comments, the default a.out generated by GCC is not a shared library but instead interpreted as a shared object by file maybe because of the content of your source code. Check this for more information.

Upvotes: 1

R.. GitHub STOP HELPING ICE
R.. GitHub STOP HELPING ICE

Reputation: 215193

The file utility is just incorrect in calling your program a shared library. It is a position-independent executable (PIE). If you really don't want this, you can specify -no-pie at link time, or build a gcc toolchain with --disable-default-pie, but in general you shouldn't need to change this.

Upvotes: 4

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