CODEWITHSUNDEEP
swiftclassobjectnstaggedpointerstring
Nyein Ei Ei Tun
Nyein Ei Ei Tun

Reputation: 168

Could not cast value of type 'NSTaggedPointerString' (0x10146ecd8) to 'NSNumber' (0x102675600)

I am trying to make a loop in my code like this:

for row in rows! {
        print("Row",row)
        let pin = Pin.init(latitude: row[0] as! Float, longitude: row[1] as! Float, pinType: row[2] as! String, beaconID: row[3] as! Int, altitude: row[4] as! Float)
        pinList.append(pin)
    }

Here, row is an Any and I'm creating the pin object based on the row's values.

Here is my Pin Class:

class Pin {
    var latitude:Float
    var longitude:Float
    var pinType:String
    var beaconID:Int
    var altitude:Float

    init(latitude:Float, longitude:Float, pinType:String, beaconID:Int, altitude:Float){
        self.latitude = latitude
        self.longitude = longitude
        self.pinType = pinType
        self.beaconID = beaconID
        self.altitude = altitude
    }
}

But I got this error:

Could not cast value of type 'NSTaggedPointerString' (0x10146ecd8) to 'NSNumber' (0x102675600).

while I am trying to create the Pin object.

Can anyone help me to fix this problem? Thanks.

Upvotes: 3

Views: 9557

Answers (2)

XenoX
XenoX

Reputation: 409

id = Int((content[0]["id"] as! NSString).floatValue)

This works fine for me. Content is json array

Upvotes: 11

Nyein Ei Ei Tun
Nyein Ei Ei Tun

Reputation: 168

Unexpectedly, I found the answer by reading along the many documentations. Here is the solution for this problem.

for row in rows! {
        print("Row",row)
        let lat = (row[0] as! NSString).floatValue
        let lng = (row[1] as! NSString).floatValue
        let pType = (row[2] as! NSString) as String
        let bID = (row[3] as! NSString).integerValue
        let alti = (row[4] as! NSString).floatValue

        let pin = Pin.init(latitude: lat, longitude: lng, pinType: pType, beaconID: bID, altitude: alti)
        pinList.append(pin)
    }

I tried to convert all the values from row to NSString first and convert the result to the types that I really convert to. :)

Upvotes: 0

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