Reputation: 883
I created a simple a spinbox(numericUpDown) control in WPF (since there is none).
I have I created a custom Value property to which I would like to create a databinding with Model.
<UserControl x:Class="PmFrameGrabber.Views.SpinBox"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:PmFrameGrabber.Views"
mc:Ignorable="d"
d:DesignHeight="25" d:DesignWidth="100">
<UserControl.Resources>
<local:IntToStringConv x:Key="IntToStringConverter" />
</UserControl.Resources>
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition />
<ColumnDefinition Width="25" />
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition />
<RowDefinition />
</Grid.RowDefinitions>
<TextBox Name="TbValue" Grid.RowSpan="2" HorizontalContentAlignment="Right"
VerticalContentAlignment="Center" HorizontalAlignment="Stretch"
VerticalAlignment="Stretch" Text="{Binding Value, Converter={StaticResource IntToStringConverter}}"/>
<Button Name="BtPlus" Grid.Column="1" Grid.Row="0" HorizontalAlignment="Stretch" Margin="3,0,0,0"
VerticalAlignment="Center" FontSize="8" Content="+" Click="BtPlus_Click" />
<Button Name="BtMinus" Grid.Column="1" Grid.Row="1" HorizontalAlignment="Stretch" Margin="3,0,0,0"
VerticalAlignment="Center" FontSize="8" Content="-" Click="BtMinus_Click" />
</Grid>
</UserControl>
Here is the code behind:
public partial class SpinBox : UserControl
{
public static DependencyProperty ValueDP =
DependencyProperty.Register("Value", typeof(int), typeof(SpinBox), new UIPropertyMetadata(0));
// Public bindable properties
public int Value
{
get => (int)GetValue(ValueDP);
set => SetValue(ValueDP, value);
}
public SpinBox()
{
InitializeComponent();
DataContext = this;
}
private void BtPlus_Click(object sender, RoutedEventArgs e) => Value++;
private void BtMinus_Click(object sender, RoutedEventArgs e) => Value--;
}
In another view I am trying to use the control like this:
<local:SpinBox Width="80" Height="25" Value="{Binding Cam.ExposureTime, Mode=TwoWay}" />
Here I get an error: Wpf binding can only be set on a dependencyproperty of an dependencyobject
Model property is in C++/CLI written like this:
property int ExposureTime
{
void set(int value)
{
m_settings->exposureTime = value;
OnPropertyChanged(GetPropName(Camera, ExposureTime));
}
int get()
{
return m_settings->exposureTime;
}
}
Binding with this property works for other controls (textbox, labels).
I guess issue is with my custom SpinBox and with the way I created Value property. After day of digging the web I haven't found what else to do.
Upvotes: 0
Views: 52
Reputation: 128061
You're ignoring the dependency property naming convention, which requires that the DependencyProperty field must be named <PropertyName>Property
:
public static readonly DependencyProperty ValueProperty =
DependencyProperty.Register("Value", typeof(int), typeof(SpinBox));
public int Value
{
get => (int)GetValue(ValueProperty);
set => SetValue(ValueProperty, value);
}
Besides that, setting
DataContext = this;
in the UserControl constructor prevents that you can bind to an inherited DataContext.
A Binding like
<local:SpinBox Value="{Binding Cam.ExposureTime, Mode=TwoWay}" />
will not work because there is no Cam
property in the current DataContext.
So do not ever set a UserControl's DataContext explicitly.
Instead, write the "internal" bindings like this:
<TextBox Text="{Binding Value,
RelativeSource={RelativeSource AncestorType=UserControl}, ...}" />
Upvotes: 1