CODEWITHSUNDEEP
javascriptarraysloopsintegeriteration
Muckee
Muckee

Reputation: 496

Iterate over integer in javascript where each value equals a single digit

I would like to use the $.each() loop to iterate over digits in an integer. The integer is produced as the index of another array, though I'm not sure that this makes a difference.

Javascript

var words = [ "This", "is", "an", "array", "of", "words","with", "a", "length", "greater", "than", "ten." ];
var numbers = [];
$.each(words, function(i,word) {
    $.each(i, function(index,value) {
        $(numbers).append(value);
    });
});

I would like the array numbers to equal the following array:

[ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 0, 1, 1 ]

Where the last four entries, [ ... 1, 0, 1, 1 ] are generated through iteration over the indexes for the entries [ ... "than", "ten." ] in the words array.

Upvotes: 0

Views: 2313

Answers (2)

trincot
trincot

Reputation: 350270

The words themselves play no role in the output, so the input really is only the length. You could use the flatMap iterator helper here:

// The input really is only a length:
const n = 12;
const digits = n => Array.from(n+"", Number);
const numbers = Array(n).keys().flatMap(digits).toArray();
    
console.log(...numbers);

Upvotes: 0

MinusFour
MinusFour

Reputation: 14423

let words = [ "This", "is", "an", "array", "of", "words","with", "a", "length", "greater", "than", "ten." ];

let numbers = words.map((w, i) => i.toString().split('').map(Number)) //map into array of digits
    numbers = Array.prototype.concat.call(...numbers); //concat them all
 console.log(numbers);

Upvotes: 2

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