Reputation: 380
I've been trying to make this URL a workable string in C#, but unfortunately using extra "" or "@" is not cutting it. Even breaking it into smaller strings is proving difficult. I want to be able to convert the entire address into a single string.
this is the full address:
<https://my.address.com/BOE/OpenDocument/opendoc/openDocument.jsp?iDocID=ATTPCi6c.mZInSt5o3t_Xr8&sIDType=CUID&&sInstance=Last&lsMZV_MAT="+URLEncode(""+[Material].[Material - Key])+"&lsIZV_MAT=>
I've also tried this:
string url = @"https://my.address.com/BOE/OpenDocument/opendoc/openDocument.jsp?iDocID=ATTPCi6c.mZInSt5o3t_Xr8&sIDType=CUID&&sInstance=Last&lsMZV_MAT=";
string url2 = @"+ URLEncode("" +[Material].[Material - Key]) + """"";
string url3 = @"&lsIZV_MAT=";
Any help is appreciated.
Upvotes: 0
Views: 98
Reputation: 19
I just made two updates t&lsMZV_MAT=" to t&lsMZV_MAT="" AND [Material - Key])+" to [Material - Key])+""
string s = @"<https://my.address.com/BOE/OpenDocument/opendoc/openDocument.jsp?iDocID=ATTPCi6c.mZInSt5o3t_Xr8&sIDType=CUID&&sInstance=Last&lsMZV_MAT=""+ URLEncode([Material].[Material - Key])+""&lsIZV_MAT=>";
Console.Write(s);
Console.ReadKey();
Upvotes: 0
Reputation: 24957
The simplest solution is put additional quotes inside string literal and use string.Concat
to join all of them into single URL string:
string url = @"https://my.address.com/BOE/OpenDocument/opendoc/openDocument.jsp?iDocID=ATTPCi6c.mZInSt5o3t_Xr8&sIDType=CUID&&sInstance=Last&lsMZV_MAT=";
string url2 = @"""+URLEncode(""+[Material].[Material - Key])+""";
string url3 = @"&lsIZV_MAT=";
string resultUrl = string.Concat(url, url2, url3);
NB: You can use Equals
method or ==
operator to check if the generated string matches with desired URL string.
Upvotes: 1
Reputation: 352
You are missing the triple quotes at the beginning of url2
string url = @"https://my.address.com/BOE/OpenDocument/opendoc/openDocument.jsp?iDocID=ATTPCi6c.mZInSt5o3t_Xr8&sIDType=CUID&&sInstance=Last&lsMZV_MAT=";
string url2 = @"""+URLEncode(""+[Material].[Material - Key])+""";
string url3 = @"&lsIZV_MAT=";
Upvotes: 1
Reputation: 143
This may be a bit of a workaround rather than an actual solution but if you load the string from a text file and run to a breakpoint after it you should be able to find the way the characters are store or just run it from that.
You may also have the issue of some of the spaces you've added being left over which StringName.Replace could solve if that's causing issues.
I'd recommend first checking what exactly is being produced after the third statement and then let us know so we can try and see the difference between the result and original.
Upvotes: 1