Reputation:
I using sklearn to obtain tf-idf values as follows.
from sklearn.feature_extraction.text import TfidfVectorizer
myvocabulary = ['life', 'learning']
corpus = {1: "The game of life is a game of everlasting learning", 2: "The unexamined life is not worth living", 3: "Never stop learning"}
tfidf = TfidfVectorizer(vocabulary = myvocabulary, ngram_range = (1,3))
tfs = tfidf.fit_transform(corpus.values())
Now I want to view my calculated tf-idf scores in a matrix as follows.
I tried to do it as follows.
idf = tfidf.idf_
dic = dict(zip(tfidf.get_feature_names(), idf))
print(dic)
However, then I get the output as follows.
{'life': 1.2876820724517808, 'learning': 1.2876820724517808}
Please help me.
Upvotes: 6
Views: 13659
Reputation: 21
I found another possible approach using toarray() function
import pandas as pd
print(tfidf.get_feature_names())
print(tfs.toarray())
print(pd.DataFrame(tfs.toarray(),
columns=tfidf.get_feature_names(),
index=['doc1','doc2','doc3'])) `
Upvotes: 1
Reputation: 119
The Answer provided by the questioner is right , I would like to make one adjustment. The above code gives
Doc1 Doc2
feature1
feature2
The matrix should be looking like this
feature1 feature2
Doc1
Doc2
so you can make a simple change to get it
df = pd.DataFrame(tfs.todense(), index=corpus_index, columns=feature_names)
Upvotes: 3
Reputation:
Thanks to σηγ I could find an answer from this question
feature_names = tfidf.get_feature_names()
corpus_index = [n for n in corpus]
import pandas as pd
df = pd.DataFrame(tfs.T.todense(), index=feature_names, columns=corpus_index)
print(df)
Upvotes: 7