Reputation: 6107
For example:
class Test {
var name: String;
var age: Int;
var height: Double;
func convertToDict() -> [String: AnyObject] { ..... }
}
let test = Test();
test.name = "Alex";
test.age = 30;
test.height = 170;
let dict = test.convertToDict();
dict will have content:
{"name": "Alex", "age": 30, height: 170}
Is this possible in Swift?
And can I access a class like a dictionary, for example probably using:
test.value(forKey: "name");
Or something like that?
Upvotes: 45
Views: 67235
Reputation: 443
A bit late to the party, but I think this is a great opportunity for JSONEncoder
and JSONSerialization
.
The accepted answer does touch on this, this solution saves us calling JSONSerialization
every time we access a key, but same idea!
extension Encodable {
/// Encode into JSON and return `Data`
func jsonData() throws -> Data {
let encoder = JSONEncoder()
encoder.outputFormatting = .prettyPrinted
encoder.dateEncodingStrategy = .iso8601
return try encoder.encode(self)
}
}
You can then use JSONSerialization
to create a Dictionary
if the Encodable
should be represented as an object in JSON (e.g. Swift Array
would be a JSON array).
Here's an example:
struct Car: Encodable {
var name: String
var numberOfDoors: Int
var cost: Double
var isCompanyCar: Bool
var datePurchased: Date
var ownerName: String? // Optional
}
let car = Car(
name: "Mazda 2",
numberOfDoors: 5,
cost: 1234.56,
isCompanyCar: true,
datePurchased: Date(),
ownerName: nil
)
// Get the encoded JSON data
let jsonData = try car.jsonData()
// To get a dictionary from the JSON data
let json = try JSONSerialization.jsonObject(with: jsonData, options: [])
guard let dictionary = json as? [String : Any] else { return }
// Use dictionary...
// Print jsonString
guard let jsonString = String(data: jsonData, encoding: .utf8) else { return }
print(jsonString)
Output:
{
"numberOfDoors" : 5,
"datePurchased" : "2020-03-04T16:04:13Z",
"name" : "Mazda 2",
"cost" : 1234.5599999999999,
"isCompanyCar" : true
}
Upvotes: 10
Reputation: 73
This answer is like the above which uses Mirror. But consider the nested class/struct case.
extension Encodable {
func dictionary() -> [String:Any] {
var dict = [String:Any]()
let mirror = Mirror(reflecting: self)
for child in mirror.children {
guard let key = child.label else { continue }
let childMirror = Mirror(reflecting: child.value)
switch childMirror.displayStyle {
case .struct, .class:
let childDict = (child.value as! Encodable).dictionary()
dict[key] = childDict
case .collection:
let childArray = (child.value as! [Encodable]).map({ $0.dictionary() })
dict[key] = childArray
case .set:
let childArray = (child.value as! Set<AnyHashable>).map({ ($0 as! Encodable).dictionary() })
dict[key] = childArray
default:
dict[key] = child.value
}
}
return dict
}
}
Upvotes: 3
Reputation: 4467
Use protocol, it is an elegant solution.
1. encode struct or class to data
2. decode data and transfer to dictionary.
/// define protocol convert Struct or Class to Dictionary
protocol Convertable: Codable {
}
extension Convertable {
/// implement convert Struct or Class to Dictionary
func convertToDict() -> Dictionary<String, Any>? {
var dict: Dictionary<String, Any>? = nil
do {
print("init student")
let encoder = JSONEncoder()
let data = try encoder.encode(self)
print("struct convert to data")
dict = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as? Dictionary<String, Any>
} catch {
print(error)
}
return dict
}
}
struct Student: Convertable {
var name: String
var age: Int
var classRoom: String
init(_ name: String, age: Int, classRoom: String) {
self.name = name
self.age = age
self.classRoom = classRoom
}
}
let student = Student("zgpeace", age: 18, classRoom: "class one")
print(student.convertToDict() ?? "nil")
Upvotes: 3
Reputation: 13632
You could use Reflection and Mirror like this to make it more dynamic and ensure you do not forget a property.
struct Person {
var name:String
var position:Int
var good : Bool
var car : String
var asDictionary : [String:Any] {
let mirror = Mirror(reflecting: self)
let dict = Dictionary(uniqueKeysWithValues: mirror.children.lazy.map({ (label:String?, value:Any) -> (String, Any)? in
guard let label = label else { return nil }
return (label, value)
}).compactMap { $0 })
return dict
}
}
let p1 = Person(name: "Ryan", position: 2, good : true, car:"Ford")
print(p1.asDictionary)
["name": "Ryan", "position": 2, "good": true, "car": "Ford"]
Upvotes: 44
Reputation: 236418
You can just add a computed property to your struct
to return a Dictionary
with your values. Note that Swift native dictionary type doesn't have any method called value(forKey:)
. You would need to cast your Dictionary
to NSDictionary
:
struct Test {
let name: String
let age: Int
let height: Double
var dictionary: [String: Any] {
return ["name": name,
"age": age,
"height": height]
}
var nsDictionary: NSDictionary {
return dictionary as NSDictionary
}
}
You can also extend Encodable
protocol as suggested at the linked answer posted by @ColGraff to make it universal to all Encodable
structs:
struct JSON {
static let encoder = JSONEncoder()
}
extension Encodable {
subscript(key: String) -> Any? {
return dictionary[key]
}
var dictionary: [String: Any] {
return (try? JSONSerialization.jsonObject(with: JSON.encoder.encode(self))) as? [String: Any] ?? [:]
}
}
struct Test: Codable {
let name: String
let age: Int
let height: Double
}
let test = Test(name: "Alex", age: 30, height: 170)
test["name"] // Alex
test["age"] // 30
test["height"] // 170
Upvotes: 95