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angularjsjsonif-statementconditional-statements
JP Dolocanog
JP Dolocanog

Reputation: 451

AngularJS - Efficient way of checking values inside a json element

I have a json object example

var obj = { a: "sample", b: "sample", c: "sample" };

and I want to check each key if they have the same values.

if(a === b || b === c || c === a){ 
  console.log("Error");
}

is there a better way of checking these values? Any ideas would be helpful. Thank you!

Upvotes: 1

Views: 172

Answers (3)

Faly
Faly

Reputation: 13356

You can use Object.keys and array.every and compare all values with the first one:

var obj = { a: "sample", b: "sample", c: "sample" };
var keys = Object.keys(obj);
var first = obj[keys[0]]
var sameValue = keys.every(key => obj[key] === first);
console.log(sameValue);

EDIT:

In case you want to return true if at least two properties have the same value:

var obj = { a: "sample", b: "saxmple", c: "sample" };
var keys = Object.keys(obj);
var sameValue = keys.some((key, index) => keys.some((otherKey, otherIndex) => obj[key] === obj[otherKey] && index !== otherIndex));
console.log(sameValue);

Upvotes: 1

uksz
uksz

Reputation: 18699

The code you posted will never print Error.

You are referencing values that do not exist.

Fix this with:

if(obj.a === obj.b || obj.b === obj.c || obj.c === obj.a){ 
  console.log("Error");
}

You can also do it with:

var firstObj = '';
var i = 0;
var areDifferent = false;
for var prop in obj {
  if (i == 0){ 
     firstObj = obj[property]
  }
  if (firstObj != obj[property]){
    areDifferent = true;
  }
  i++;
}

if (areDifferent){
 //your code here
}

The code above will run through all obj properties, to check if all of them are equal to the first one - which means, that are of them are equal.

Upvotes: 1

101
101

Reputation: 1

try this _.every from Underscore.js

every_.every(list, [predicate], [context])

Returns true if all of the values in the list pass the predicate truth test. Short-circuits and stops traversing the list if a false element is found.

_.every([2, 4, 5], function(num) { return num % 2 == 0; }); => false

in ur case u should check value of the first element of "obj" with all next elements in "obj"

Upvotes: -1

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