CODEWITHSUNDEEP
swiftstringurl
doej
doej

Reputation: 569

Delete parameter from URL with swift

I have an URL that looks like myapp://jhb/test/deeplink/url?id=4567 . I want to delete every thing after the ? char. At the end the URL should look like myapp://jhb/test/deeplink/url. how. can I achieve that? convert the url to a string? Regex?

Upvotes: 13

Views: 11668

Answers (5)

Ahmad F
Ahmad F

Reputation: 31645

can I achieve that? convert the url to a string? Regex?

When working with URLs, it would be better to treat it as URLComponent:

A structure that parses URLs into and constructs URLs from their constituent parts.

therefore, referring to URLComponent what are you asking is to remove the the query subcomponent from the url:

if var components = URLComponents(string: "myapp://jhb/test/deeplink/url?id=4567") {
    components.query = nil
    
    print(components) // myapp://jhb/test/deeplink/url
}

Note that query is an optional string, which means it could be nil (as mentioned in the code snippet, which should leads to your desired output).

Upvotes: 4

onmyway133
onmyway133

Reputation: 48135

A convenient extension on URL


private extension URL {
    var removingQueries: URL {
        if var components = URLComponents(string: absoluteString) {
            components.query = nil
            return components.url ?? self
        } else {
            return self
        }
    }
}

Upvotes: 9

luk2302
luk2302

Reputation: 57154

Use URLComponents to separate the different URL parts, manipulate them and then extract the new url:

var components = URLComponents(string: "myapp://jhb/test/deeplink/url?id=4567")!
components.query = nil
print(components.url!)

myapp://jhb/test/deeplink/url

Upvotes: 17

Varun Naharia
Varun Naharia

Reputation: 5428

You can get each URL component separated from URl using 

print("\(url.host!)") //Domain name
print("\(url.path)") // Path
print("\(url.query)") // query string

Upvotes: 0

Usman Javed
Usman Javed

Reputation: 2455

You can do like this 

let values = utl?.components(separatedBy: "?")[0]

It will break the string with ? and return the array. The first object of values give you your resultant string.

Upvotes: 0

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