Reputation: 1769
Code statement look like below:
if((temp1 == ID1) || (temp2 == (C_UINT16) ID2))
{
}
I am not sure why QAC is generating this warning. What will be the side effect & how to avoid this warning.
Details for QAC-help:
The right hand operand of a logical && operator is only evaluated if the left hand operand evaluates to 1 ("true"). The right hand operand of a logical || operator is only evaluated if the left hand operand evaluates to 0 ("false").
Because of this behaviour, confusion can arise if the right hand operand of either of these operators generates side effects. Message 3415 is generated to identify such a situation.
Side effects occur when an expression:
However QAC assumes that side effects occur whenever a function is called, unless the function has specifically been identified as being free from side effects by a #pragma statement of the form:
#pragma PRQA_NO_SIDE_EFFECTS funcname
Upvotes: 1
Views: 10374
Reputation: 1769
While looking at variable temp1 & temp2. I got to know it is declared as volatile. After changing the variable to the normal non-volatile, the warning is not observed. It was level 4 warning in QAC.
Reference: https://cboard.cprogramming.com/c-programming/68666-strange-side-effects.html
Another way to resolve the error to read the volatile variable again before performing the operation again.
Upvotes: 0