CODEWITHSUNDEEP
pythontuplesdifference
Nagarajan Shanmuganathan
Nagarajan Shanmuganathan

Reputation: 408

Finding the missing elements among two tuples in Python

I have two tuples a = (('1',), ('2',), ('3',),) and b = (('1',), ('3',),). I need to get the result as (('2',),) since, 2 is the element that is present in a and not in b.

I referred this Find intersection of two lists? and Is there a way to get the difference and intersection of tuples or lists in Python? for getting an idea, but these are for lists and not for tuples. I am not able to use intersection() for tuples.

Is there a way I can get a-b in python tuples?

Upvotes: 2

Views: 1641

Answers (3)

Duc Filan
Duc Filan

Reputation: 7157

Convert to set then you can get the difference, then convert it back to tuple using tuple() function:

a = (('1',), ('2',), ('3',),)
b = (('1',), ('3',),)

result = tuple(set(a) - set(b))
print(result)

Running example: https://repl.it/M1FD/1

If you want the Symmetric Difference, elements in either set but not in the intersection:

set(a) ^ set(b)

or:

set(a).symmetric_difference(set(b))

Running example: https://repl.it/M1FD/2

Upvotes: 3

teambob
teambob

Reputation: 2084

You can still use sets as described in the linked answer:

In [1]: a = (('1',), ('2',), ('3',),)
In [2]: b = (('1',), ('3',),)
In [3]: set(a).intersection(set(b))
Out[3]: {('1',), ('3',)}
In [4]: set(a).difference(set(b))
Out[4]: {('2',)}

Upvotes: 0

David Scarlett
David Scarlett

Reputation: 3341

Sets are very useful for this.

If you're only looking for elements that are in a but not in b:

set(a) - set(b)

If you're looking for elements that are in either one of the tuples, but not the other:

set(a) ^ set(b)

Upvotes: 1

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