Reputation: 297
My question is the title. I have tried this:
public void UploadToFtp(List<strucProduktdaten> ProductData)
{
ProductData.ForEach(delegate( strucProduktdaten data )
{
ZipFile.CreateFromDirectory(data.Quellpfad, data.Zielpfad, CompressionLevel.Fastest, true);
});
}
static void Main(string[] args)
{
List<strucProduktdaten> ProductDataList = new List<strucProduktdaten>();
strucProduktdaten ProduktData = new strucProduktdaten();
ProduktData.Quellpfad = @"Path\to\zip";
ProduktData.Zielpfad = @"Link to the ftp"; // <- i know the link makes no sense without a connect to the ftp with uname and password
ProductDataList.Add(ProduktData);
ftpClient.UploadToFtp(ProductDataList);
}
Error:
System.NotSupportedException:"The Path format is not supported."
I have no idea how I should connect in this case to the FTP server and zipping the directory in ram and send it directly to the server.
... can someone help or have a link to a similar or equal problem what was solved?
Upvotes: 3
Views: 3613
Reputation: 202594
Create the ZIP archive in MemoryStream
and upload it.
using (Stream memoryStream = new MemoryStream())
{
using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
{
foreach (string path in Directory.EnumerateFiles(@"C:\source\directory"))
{
ZipArchiveEntry entry = archive.CreateEntry(Path.GetFileName(path));
using (Stream entryStream = entry.Open())
using (Stream fileStream = File.OpenRead(path))
{
fileStream.CopyTo(entryStream);
}
}
}
memoryStream.Seek(0, SeekOrigin.Begin);
var request =
WebRequest.Create("ftp://ftp.example.com/remote/path/archive.zip");
request.Credentials = new NetworkCredential("username", "password");
request.Method = WebRequestMethods.Ftp.UploadFile;
using (Stream ftpStream = request.GetRequestStream())
{
memoryStream.CopyTo(ftpStream);
}
}
Unfortunately the ZipArchive
requires a seekable stream. Were it not, you would be able to write directly to the FTP request stream and won't need to keep a whole ZIP file in a memory.
Based on:
Upvotes: 3
Reputation: 109792
Something like this would work as far as getting the ZIP into memory goes:
public static byte[] ZipFolderToMemory(string folder)
{
using (var stream = new MemoryStream())
{
using (var archive = new ZipArchive(stream, ZipArchiveMode.Create))
{
foreach (var filePath in Directory.EnumerateFiles(folder))
{
var entry = archive.CreateEntry(Path.GetFileName(filePath));
using (var zipEntry = entry.Open())
using (var file = new FileStream(filePath, FileMode.Open))
{
file.CopyTo(zipEntry);
}
}
}
return stream.ToArray();
}
}
Once you have the byte array, you should readily be able to send it to the server.
Upvotes: 1