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javascriptarraysreactjsloopssearch
Hayk Shakhbazyan
Hayk Shakhbazyan

Reputation: 242

Javascript - matching first value from array search with value from other array

So let's say we have two arrays

const arr1 = [1, 2, 3, 4, 5];

const arr2 = [6, 7, 8, 9, 10, 4, 5,];

I want to return just the first matching value without doing two for loops. So not by taking first value from arr1 look for it in arr2 then second value ect.

I this case I would need to return 4.

Working in React/Redux enviroment without jQuery possible.

Upvotes: 1

Views: 81

Answers (4)

Nina Scholz
Nina Scholz

Reputation: 386654

You could use the power of Set.

const
    arr1 = [1, 2, 3, 4, 5],
    arr2 = [6, 7, 8, 9, 10, 4, 5],
    result = arr2.find((s => a => s.has(a))(new Set(arr1)));

console.log(result);

Upvotes: 0

RomanPerekhrest
RomanPerekhrest

Reputation: 92854

Ecmascript5 solution (with Array.some() function):

var arr1 = [1, 2, 3, 4, 5],
    arr2 = [6, 7, 8, 9, 10, 4, 5,],
    result;
	
arr2.some(function(n){ return arr1.indexOf(n) !== -1 && (result = n) })

console.log(result);

Upvotes: 0

Nenad Vracar
Nenad Vracar

Reputation: 122057

You can use find() with includes() method.

const arr1 = [1, 2, 3, 4, 5];
const arr2 = [6, 7, 8, 9, 10, 4, 5,];

var r = arr1.find(e => arr2.includes(e));
console.log(r)

Upvotes: 0

BenW
BenW

Reputation: 1312

const arr1 = [1, 2, 3, 4, 5];

const arr2 = [6, 7, 8, 9, 10, 4, 5,];

arr1.find((x) => arr2.indexOf(x) >=0);

That'll grab the first match

Upvotes: 3

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