Reputation: 3
I have three tables User, Users_clients, and Credits. I want to list tables of current user's clients with their details and credit. If any client is listed in credit table then credit should return 0 where else it should return the credit value.
my model.py is
class User_clients(models.Model):
user = models.ForeignKey(User, related_name='myuser')
client = models.ForeignKey(User, related_name='myclient')
class Credits(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
credit = models.IntegerField(null=True, default=0)
my views.py is
def clients(request):
try:
data = User_clients.objects.order_by('-id').filter(user_id=request.user.id)[0:10]
except User_clients.DoesNotExist:
data = None
return render(request, "client_list.html",{'title':"Client List",'clients':data,'active':'myclients','open':'clients'})
Thanks a lot in advance!
Upvotes: 0
Views: 562
Reputation:
updating after your comment:
from itertools import chain
from django.db.models import F
without_credit = User_clients.objects.filter(user=request.user, client__credits__is_null=True).annotate(credit=0)
with_credit = User_clients.objects.filter(user=request.user,
client__credits__is_null=False).annotate(credit=F("client__credits__credit"))
data = chain(without_credit, with_credit)
Upvotes: 1