CODEWITHSUNDEEP
phpregex
Ste
Ste

Reputation: 1520

Php preg_match using URL as regex

i have an array of urls

[
  'http://www.example.com/eng-gb/products/test-1',
  'http://www.example.com/eng-gb/products/test-3',
  'http://www.example.com/eng-gb/about-us',
]

I need to write a regex for filter only the ones end with:

http://www.example.com/eng-gb/products/(.*)

in this case i need to exclude 'about-us'.

I need also use 'http://www.example.com/eng-gb/products/(.*)' as regex.

The best way for archive?

Upvotes: 3

Views: 2108

Answers (3)

mickmackusa
mickmackusa

Reputation: 47864

preg_grep() provides a shorter line of code, but because the substring to be matched doesn't appear to have any variable characters in it, best practice would indicate strpos() is better suited.

Code: (Demo)

$urls=[
  'http://www.example.com/eng-gb/products/test-1',
  'http://www.example.com/eng-gb/badproducts/test-2',
  'http://www.example.com/eng-gb/products/test-3',
  'http://www.example.com/eng-gb/badproducts/products/test-4',
  'http://www.example.com/products/test-5',
  'http://www.example.com/eng-gb/about-us',
];

var_export(preg_grep('~^http://www.example\.com/eng-gb/products/[^/]*$~',$urls));
echo "\n\n";
var_export(array_filter($urls,function($v){return strpos($v,'http://www.example.com/eng-gb/products/')===0;}));

Output:

array (
  0 => 'http://www.example.com/eng-gb/products/test-1',
  2 => 'http://www.example.com/eng-gb/products/test-3',
)

array (
  0 => 'http://www.example.com/eng-gb/products/test-1',
  2 => 'http://www.example.com/eng-gb/products/test-3',
)

Some notes:

Using preg_grep():

  • Use a non-slash pattern delimiter so that you don't have to escape all of the slashes inside the pattern.
  • Escape the dot at .com.
  • Write the full domain and directory path with start and end anchors for tightest validation.
  • Use a negated character class near the end of the pattern to ensure that no additional directories are added (unless of course you wish to include all subdirectories).
  • My pattern will match a url that ends with /products/ but not /products. This is in accordance with the details in your question.

Using strpos():

  • Checking for strpos()===0 means that the substring must be found at the start of the string.
  • This will allow any trailing characters at the end of the string.

Upvotes: 1

B. Fleming
B. Fleming

Reputation: 7220

You'll need to escape the forward slashes and periods to get http:\/\/www\.example\.com\/eng-gb\/products\/(.*). After that, you could just place the URL in directly.

Alternatively (better) would be to search for \/eng-gb\/products\/(.*).

Example:

$matches = array();
preg_match('/\/eng-gb\/products\/(.*)/', $your_url, $matches);
$product = $matches[1];

Upvotes: 0

ilicmsreten
ilicmsreten

Reputation: 468

I think you need use preg_grep cause you have array of urls and this will return array of url that match your condition

$matches = preg_grep('/products\/.*$/', $urls);

and also you can use validate filters in php to validate urls

Upvotes: 0

Related Questions