CODEWITHSUNDEEP
phparraysrandomforeach
hendra
hendra

Reputation: 83

PHP generate foreach and generate it as array

please help I need create some array random from this case:

foreach (range(1,3) as $number) { 
$lala1= "\"img$number\",";
$lala2 = array("$lala1");
echo $lala2[array_rand($lala2)];
}

Is give me this result:

"img1","img2","img3",

but I need the result to show random like this:

img1 (with random img1,img2, or img3)

Thank you

Upvotes: 2

Views: 62

Answers (2)

ishegg
ishegg

Reputation: 9947

You are making a one element array ($lala2) and "randomizing" it on each iteration, which is why you get all 3 elements printed out.

What you need to do is add a new element on each iteration, and only then use array_rand() to pick a random element out of the resulting array:

<?php
$imgs = []; // define the array where you'll store the elements
foreach (range(1,3) as $number) { 
    $lala1 = "\"img$number\",";
    $imgs[] = $lala1; // add the new element to the array
}
echo $imgs[array_rand($imgs)]; // pick a random value

Demo

Upvotes: 3

Barmar
Barmar

Reputation: 781706

You need to add to the array each time through the loop, not replace it, and then use array_rand() after the loop.

$lala2 = array();
foreach (range(1, 3) as $number) {
    $lala1 = "\"$img$number\",";
    $lala2[] = $lala1;
}
echo $lala2[array_rand($lala2)];

Upvotes: 1

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