CODEWITHSUNDEEP
c++operators
Ashim
Ashim

Reputation: 927

Pre-Decrement Operator

My question is related to calling a function as well as decrement operator. The answer for the following code is 20 1 19 10 My question is that after "--m" the m should be 19 so it should send 19 and finally 19 should be print giving output 19 1 19 10 but why is m not changing even though there is "--m"?

void f(int a, double b){cout<< a--<< '\t'<< b<< endl;}

int g(double x, int y){ return (x / ++y);}

int main()
{

int m = 20, n = 10;

f(m, g(--m, n));

cout<< m<< '\t'<< n << endl;

return 0;

}

Upvotes: 0

Views: 52

Answers (1)

Christophe
Christophe

Reputation: 73542

This is unspecified behavior. The C++ doesn't state the order of evaluation of parameters.

Upvotes: 3

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