Reputation: 11
I need my output to only be 5 characters long NOT counting the removed vowels. Currently my code is counting the input length and returning that number minus the vowels. This might be confusing. If I input "idontthinkso" it only returns "dnt" instead of what I want it to print out which is "dntth". Btw, I'm not allowed to use Stringbuilder or anything like that, only a loop, so forgive the code. How can I fix this? Here is my code:
import java.util.Scanner;
public class TweetCompressor {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
String s = "";
System.out.println("Type a tweet: ");
String input = keyboard.nextLine();
int f = 0;
int tweetLengthAllowed = 5;
for (int i = 0; i < tweetLengthAllowed; i++) {
char c = input.charAt(i);
if (c == 'a' ||
c == 'e' ||
c == 'i' ||
c == 'o' ||
c == 'u' ||
c == 'A' ||
c == 'E' ||
c == 'I' ||
c == 'O' ||
c == 'U') {
f = 1;
} else {
s = s += c;
f = 0;
}
}
System.out.println(s);
}
}
Upvotes: 1
Views: 1788
Reputation: 343
Here is my way of doing it:-
import java.util.Scanner;
import java.lang.StringBuffer;
public class Program {
private static String RemoveVowel(String text)
{
int len = text.length();
char[]vowels = {'a','e','i','o','u','A','E','I','O','U'};
StringBuffer sb = new StringBuffer(text);
for(int i = 0;i<len;i++)
{
for(char v : vowels)
{
if(v == text.charAt(i))
{
sb.setCharAt(i,'\0');
}
}
}
return sb.toString();
}
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
System.out.print("Enter some text to remove vowels from it: ");
String val = scan.nextLine();
System.out.println(RemoveVowel(val));
}
}
I have used string buffer to make the string modifiable and a "for" loop iterates through the length of the string, and one iterates through the "vowels" array; an "if" statement checks if the current character is equal to one of the vowels and if true, it sets the current character to null, which removes the vowel.
Upvotes: 1
Reputation: 1
public class RemoveVowels {
public static void main(String[] args) {
String inputString = "Java - Object Oriented Programming Language";
System.out.println(inputString.replaceAll("[aeiouAEIOU]", " "));
}
}
Output:
J v - bj ct r nt d Pr gr mm ng L ng g
Upvotes: 0
Reputation: 5794
You can do this simpler. Here I iterate every char in the input and break if it reaches the limit:
import java.util.Scanner;
public class TweetCompressor {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
String s = "";
System.out.println("Type a tweet: ");
String input = keyboard.nextLine();
int tweetLengthAllowed = 5;
int i = 0;
boolean isNotVowel;
boolean limitReached;
for (char c : input.toCharArray()) {
isNotVowel = "AEIOUaeiou".indexOf(c) == -1;
limitReached = tweetLengthAllowed <= i;
if (limitReached) { // exit the loop
break;
} else if (isNotVowel) { // append the char
s += c;
i++;
}
}
System.out.println(s);
}
}
Run output:
Type a tweet:
idontthinkso
dntth
Upvotes: 1
Reputation: 41
I'm very much in favor of using a while loop for this, but since you stated you can only use a for loop...
The problem is that your loop will iterate until i = 5, even if a vowel is detected. We need a way to tell the loop to pretend that never happened. You can't decrement i, or you'll be stuck at the same character forever.
Here's what I came up with, I decided to simply increment the tweetLengthAllowed
to negate the i increment.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
String s = "";
System.out.println("Type a tweet: ");
String input = keyboard.nextLine();
int f = 0;
int tweetLengthAllowed = 5;
for(int i = 0; i < tweetLengthAllowed; ++i) { //Must be a for loop
char c = input.charAt(i);
if(c == 'a'|| c == 'e'|| c == 'i'|| c == 'o'|| c =='u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') {
f = 1;
tweetLengthAllowed++; //Allows the loop to continue for one more interation
} //end if
else{
s = s += c;
f = 0;
}//end else
} //end for
System.out.println(s);
} //end main
} //end class
Also, if you're going to use a big chain of ORs, please do yourself a favor and make it more readable as I did above.
Upvotes: 1