CODEWITHSUNDEEP
javascriptjqueryfunctionloopsdynamic-function
Martin AJ
Martin AJ

Reputation: 6697

How can I make dynamic functions?

I have 10 functions like these:

function instagram_ajax(){
    return ajaxRequest('search/instagramid', 'instagramid').then(
        function(res) {
            var imgStatus = res[1].length > 0 ? "checked_successfully.png" : "checked_noRes.png";
            $('.option_name_instagramid + td').html("<img src='img/" + imgStatus + "' />")

            optionsRes['instagramid'] = res[1];

        }, function(err){
            $('.option_name_instagramid + td').html("<img src='img/warning.png' />")
        }
    );
}

function googleplus_ajax(){
    return ajaxRequest('search/googleplusid', 'googleplusid').then(
        function(res) {
            var imgStatus = res[1].length > 0 ? "checked_successfully.png" : "checked_noRes.png";
            $('.option_name_googleplusid + td').html("<img src='img/" + imgStatus + "' />")

            optionsRes['googleplusid'] = res[1];

        }, function(err){
            $('.option_name_googleplusid + td').html("<img src='img/warning.png' />")
        }
    );
}

.
.
.

As you see, those functions are almost equivalent, just the difference is words instagram, googleplus. Also I have an array of all those names:

var parts = ['instagram', 'googleplus', 'linkedin', 'facebook', ...];

Now I want to know, is it possible to make those array dynamically? I mean by putting a variable-base function into a loop and use that array to make all those functions? Is such a thing possible?

Upvotes: 0

Views: 42

Answers (1)

notrota
notrota

Reputation: 1088

make a wrappper function

function ajax(str) {
  return function() {
    return ajaxRequest('search/'+str+'id', ''+str+'id').then(
        function(res) {
            var imgStatus = res[1].length > 0 ? "checked_successfully.png" : "checked_noRes.png";
            $('.option_name_'+str+'id + td').html("<img src='img/" + imgStatus + "' />")

            optionsRes[str+'id'] = res[1];

        }, function(err){
            $('.option_name_'+str+'id + td').html("<img src='img/warning.png' />")
        }
    );
  }
}

var instagram_ajax = ajax('instagram');
var googleplus_ajax = ajax('googleplus');

or for your case

var parts = ['instagram', 'googleplus', 'linkedin', 'facebook'];

var funcs = {};
for (var i = 0; i < parts.length; i++)
  funcs[parts[i]] = ajax(parts[i]);

// now u do
funcs.instagram()

Upvotes: 3

Related Questions