CODEWITHSUNDEEP
regexbashsortingunixgrep
N3o
N3o

Reputation: 53

grep command to find out how many times any character is followed by '.'

I have to find out how often any character is followed by a period (.) with the help of grep. After finding how many times character is followed by period and then I have to sort the result in ascending order.

For example in this string: "Find my input. Output should be obtained. You need to find output."

The output should be something like this:

d 1 
t 2

What I have done so far : 

cat filename | grep -o "*." | sort -u

But it is not working as intended.

Any ideas how to solve this? I have to perform this operation on huge library of books in .txt files.

Upvotes: 3

Views: 117

Answers (3)

ctac_
ctac_

Reputation: 2471

This one is ok too

echo "Find my input. Output should be obtained. You need to find output."| grep -o ".\." | sort | uniq -c | rev | tr -d .

Upvotes: 0

RomanPerekhrest
RomanPerekhrest

Reputation: 92854

With single GNU awk process:

awk -v FPAT='.[.]' 'BEGIN{ PROCINFO["sorted_in"]="@ind_str_asc" }
       { for(i=1;i<=NF;i++) a[substr($i,1,1)]++ }
       END{ for(i in a) print i,a[i] }' filename

The output:

d 1
t 2

Upvotes: 0

Cyrus
Cyrus

Reputation: 88684

An iterative approach with GNU grep:

grep -o '.\.' filename | sort | uniq -c

Output:

          1 d.
          2 t.

grep -Po '.(?=\.)' filename | sort | uniq -c

Output:

          1 d
          2 t

grep -Po '.(?=\.)' filename | sort | uniq -c | awk '{print $2,$1}'

Output:

d 1
t 2

Upvotes: 4

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