Reputation: 19534
table: uuid, version, datetime
version is not unique, but the idea is to fetch only the rows with the latest datetime for a given uuid
SELECT * FROM table WHERE uuid='bla' GROUP BY version ORDER BY datetime desc
... of course gets datetime asc results -- is there a way to "preorder" the group by to desc, so that only the latest version is fetched?
Upvotes: 8
Views: 35540
Reputation: 1
I used a separate method on php to get the id's and put it into an array. Then on another sql query i searched the data by looking up the id's
$ids = array();
$sql = "SELECT pid FROM table_name WHERE DATE(column_name)='yyyy-mm-dd' ORDER BY column_name ASC";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
if (!in_array($row['value'], $ids)) {
array_push($ids, $row['value']);
}
}
}
And then
$sql = "SELECT * FROM table_name WHERE id IN (".implode(',', $ids).") ORDER BY column_name ASC";
Upvotes: 0
Reputation: 18583
There is a better way for me, you could add a desc
to group by:
SELECT * FROM table WHERE uuid='bla' GROUP BY version desc
why it works is because my id's are generated and so always the latest id means the latest datetime
Upvotes: 2
Reputation: 71
SELECT * FROM
(SELECT * FROM table WHERE uuid='bla' ORDER BY datetime desc) table
GROUP BY version;
Upvotes: 6
Reputation: 30111
since the table only has those 3 field, and you are filtering by uid you can just use the MAX without the JOIN:
SELECT version, MAX(datetime) Maxdatetime
FROM table
WHERE uuid='bla'
GROUP BY version
However, if the table had more fields, or you are not filtering by uid
- you need to first get the MAX datetime for each version, then select the row:
SELECT t.uuid, t.version, t.datetime
FROM table t JOIN (
SELECT version, MAX(datetime) Maxdatetime
FROM table
WHERE uuid='bla'
GROUP BY version
) r ON t.version = r.version AND t.datetime = r.Maxdatetime
WHERE t.uuid='bla'
ORDER BY t.datetime desc
Upvotes: 26