CODEWITHSUNDEEP
python
Glaube
Glaube

Reputation: 19

Python - Scrabble_score

Can someone break down the individual components that make up scrabble_score:

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
    "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
    "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
    "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
    "x": 8, "z": 10}

def scrabble_score(word):
    return sum([score[x] for x in word.replace(" ", "").lower() if x in score])

Upvotes: 0

Views: 690

Answers (3)

Bar Amrani
Bar Amrani

Reputation: 1

you can use this code for solution

total_score variable is to sum letter score. the score[char.lower()] is for code that will work even if the letters you get are uppercase, lowercase, or a mix

 def scrabble_score (word):
  total_score=0
  for char in word:
    total_score+=score[char.lower()]
  return total_score

Upvotes: 0

Aaron
Aaron

Reputation: 11075

broken down (in bold)...

return sum([score[x] for x in word.replace(" ", "").lower() if x in score])

removes all spaces and converts to all lower case

return sum([score[x] for x in word.replace(" ", "").lower() if x in score])

for each letter after removing spaces and converting to lower case

return sum([score[x] for x in word.replace(" ", "").lower() if x in score])

if that letter is in the score dictionary

return sum([score[x] for x in word.replace(" ", "").lower() if x in score])

get the score for that letter and add it to a list

return sum([score[x] for x in word.replace(" ", "").lower() if x in score])

after getting the score for each letter, add up the sum of the resulting list of values and return

Upvotes: 0

Adam Smith
Adam Smith

Reputation: 54223

The structure is a list comprehension. This is a terse way of creating a list from an iterable. See below where the 1s are list comps and the 2s are traditional for loops.

result1 = [some_value for element in iterable]
# where the group of "value" statements is the final list

result2 = []
for element in iterable:
    result2.append(some_value)

example1 = [x**2 for x in range(10)]  #  [0**2, 1**2, 2**2, ..., 9**2]
example2 = []
for x in range(10):
    example2.append(x)

This particular listcomp is using a dict lookup (score[x]) as the value of the list, where x is each element of word.replace(" ", "").lower(). It also uses a conditional filtering statement at the end to make sure it only selects those elements where x is in score (so something like it's doesn't fail on the '.)

Wrapped around it is sum, which simply adds all the numbers in a list and gives the result.

Upvotes: 1

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