CODEWITHSUNDEEP
bashshell
Matt
Matt

Reputation: 41

Bash -1 year from date

Year=`date '+%Y'`
RTRN1=$?

This returns the current date in the logs, however i want to return the year before, so instead of this returning 2017 i want 2016.

Any help appreciated! Thanks

Upvotes: 4

Views: 5100

Answers (3)

David C. Rankin
David C. Rankin

Reputation: 84607

You can always capture the year with date +'%Y'. You can subtract 1 with the POSIX arithmetic operator, e.g.

$ echo $(($(date +%Y) - 1))
2016

You can also use the POSIX compliant expr math operators, e.g.

$ expr $(date +%Y) - 1
2016

(note: with expr you must leave a space between the math operator and the values)

The GNU date operator -d with '1 year ago' will work as specified in the comments and other answer, along with let dt=$(date +%Y)-1; echo $dt as specified in the other answer (no spaces allowed with let).

Of all the choices, if I didn't have GNU date, I'd pick the POSIX arithmetic operator $((...)) with a date command substitution minus 1.

Upvotes: 2

Matt
Matt

Reputation: 15186

As we have bash, it's possible to use let

let YEAR=`date +%Y`-1
echo $YEAR

Upvotes: 1

RomanPerekhrest
RomanPerekhrest

Reputation: 92894

For GNU date utility: use -d (--date) option to adjust the date:

Year=$(date +%Y -d'1 year ago')

echo $Year
2016

Upvotes: 7

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