Reputation: 161
I am trying add information from a second data set to my first based on ID and dates. If the ID matches and 'Date' is between 'start' and 'end', I want to add the value for colour to df1.
df1
ID Date
1 3/31/2017
2 2/11/2016
2 4/10/2016
3 5/15/2015
df2
ID start end colour
1 1/1/2000 3/31/2011 blue
1 4/1/2011 6/4/2012 purple
1 6/5/2012 3/31/2017 blue
2 5/1/2014 3/31/2017 red
3 1/12/2012 2/12/2014 purple
To get a result like this:
dat
ID Date colour
1 3/31/2017 blue
2 2/11/2016 red
2 4/10/2016 red
3 5/15/2015 NA
Which can be created with the code here:
library(lubridate)
df1 <- tibble(ID = c(1,2,2,3), Date = mdy(c("3/31/2017","2/11/2016","4/10/2016","5/15/2015")))
df2 <- tibble(ID = c(1,1,1,2,3), start = mdy(c("1/1/2000","4/1/2011","6/5/2012","5/1/2014","1/12/2012")), end = mdy(c("3/31/2011","6/4/2012","3/31/2017","3/31/2017","2/12/2014")), colour = c("blue", "purple", "blue", "red", "purple"))
I used a response from a similar question, Checking if Date is Between two Dates in R and used the code below:
library(dplyr)
dat <- inner_join(df1, df2, by = "ID")
dat %>% rowwise() %>%
mutate(match = ifelse(between(df1$Date, df2$start, df2$end), 1 , 0))%>%
select(-c(df2$start, df2$end))%>%
arrange(df1$Date, desc(match))%>%
distinct(df1$Date)
and I get the following error:
Error in between(df1$Date, df2$start, df2$end) : Expecting a single value: [extent=355368].
help?
Thanks so much!
Update-
Thanks so much everyone for your answers.
I tried them all but all the final datasets have different number of rows than the first dataset. I am not sure what is happening. The data I have posted is made-up to resemble the data I am working with. Are there additional details that I should let you know? I don't know where to start...
Upvotes: 4
Views: 1267
Reputation: 14958
dplyr
uses non standard evaluation and so you can dump all the dataframe names and $
s and your code begins basically in the right direction. There are additionally a number of implicit transformations necessary for you to end up with the data frame you specified, but this below will get you there.
dat <-
df1 %>%
inner_join(df2) %>%
rowwise %>%
mutate(match = ifelse(between(Date, start, end), 1 , NA)) %>%
arrange(ID, Date, desc(match)) %>%
ungroup %>%
group_by(ID, Date) %>%
mutate(best = row_number(ID),
colour = if_else(is.na(match), NA_character_, colour)) %>%
filter(best == 1) %>%
select(ID, Date, colour)
> dat # A tibble: 4 x 3 # Groups: ID, Date [4] ID Date colour <dbl> <date> <chr> 1 1 2017-03-31 blue 2 2 2016-02-11 red 3 2 2016-04-10 red 4 3 2015-05-15 <NA>
Upvotes: 1
Reputation: 2454
Another alternative using sqldf
library(sqldf)
df1$Date <- as.Date(df1$Date, "%m/%d/%Y")
df2$start <- as.Date(df2$start, "%m/%d/%Y")
df2$end <- as.Date(df2$end, "%m/%d/%Y")
sqldf({"
SELECT df1.*, df2.colour FROM df1
INNER JOIN df2
ON df1.ID = df2.ID AND df1.Date <= df2.end AND df1.Date >= df2.start
"})
Upvotes: 1
Reputation: 546
I reproduced your example and and give it one solution.
library(tidyverse)
library(lubridate)
df1 <- data.frame(ID=c(1, 2, 2, 3),
actual.date=mdy('3/31/2017', '2/11/2016','4/10/2016','5/15/2015'))
df2 <- data.frame(ID = c(1, 1, 1, 2, 3),
start = mdy('1/1/2000', '4/1/2011', '6/5/2012', '5/1/2014', '1/12/2012'),
end = mdy('3/31/2011', '6/4/2012', '3/31/2017', '3/31/2017', '2/12/2014'),
colour = c("blue", "purple", "blue", "red", "purple"))
df <- full_join(df1, df2, by = "ID") %>%
mutate(test = ifelse(actual.date <= end & actual.date > start,
TRUE,
FALSE)) %>%
filter(test) %>%
left_join(df1, ., by = c("ID", "actual.date")) %>%
select(ID, actual.date, colour)
(The lubridate package is not necessary, but it is handy to enter dates)
And please, next time, provide a reproducible example, so that we don't have to rewrite the data manually!
Upvotes: 1
Reputation: 214917
It seems your data frame is large, you can try data.table
non-equi join to do this in an efficient way:
library(lubridate)
library(data.table)
setDT(df1); setDT(df2)
df1[, Date := mdy(Date)]
df2[, c("start", "end") := .(mdy(start), mdy(end))]
df2[df1, .(ID = i.ID, Date = i.Date, colour), on=.(ID, start <= Date, end >= Date)]
# ID Date colour
#1: 1 2017-03-31 blue
#2: 2 2016-02-11 red
#3: 2 2016-04-10 red
#4: 3 2015-05-15 NA
Upvotes: 2