CODEWITHSUNDEEP
javascriptregex
chyltse
chyltse

Reputation: 9

Regex delimiters put back into use

I am a bit stuck on this, can't figure out how to re-insert the non-word characters ie. "-" and "!". I used regex as a way to split based on those delimiters but do need to retain the indices of the "-" and the "!" and re-introduce once I convert it back into a string from the array. The desired output is "e6t-r3s are r4y fun!" and so far I am getting: 'e6t r3s are r4y fun '

Write a function that takes a string and turns any and all "words" (see below) within that string of length 4 or greater into an abbreviation following the same rules.

abbreviate("elephant-rides are really fun!");

function abbreviate(string) {
    var array = string.split(/\W/); 
    var newArray = [];
    for (var i = 0; i < array.length; i++) {//iterates through each word
      var word = array[i];
      var abbrString = "";
      if (word.length >= 4) {
          //concat first index,count of indexes in between, last index
          var innerChar = word.substring(1, word.length - 1);
          var indCount = innerChar.length;
          var abbrWord = word.charAt(0) + indCount + word.charAt(word.length-1); 
          newArray.push(abbrWord);
        } else {
          newArray.push(word);
        }

    }
  return newArray.join(" ");
}

Upvotes: 1

Views: 48

Answers (1)

Flying
Flying

Reputation: 4570

Your code can be much simpler if you will use ability to pass a function to String.replace():

function abbreviate(str) {
    return str.replace(/[a-z]{4,}/ig, function (word) {
        return word[0] + (word.length - 2) + word[word.length - 1];
    })
}

console.log(abbreviate("elephant-rides are really fun!"));
console.log(abbreviate("Accessibility"));

Upvotes: 1

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