CODEWITHSUNDEEP
python
hima Fernando
hima Fernando

Reputation: 147

How to extract only the time from a list of date time

Here is my code to get date and time when starting time is 10 am,( (2017, 10, 29, 10, 0) and then date time until 10 am on the next day. Now, I want to extract only the time from that and get 10:00 am to 10 am on the following day . So my result should be 

(10:00,11:00,12:00,13:00,14:00,15:00,16:00,17:00,18:00,19:00,20:00,21:00,22:00,23:00,00:00,1:00,2:00,3:00,4:00,5:00,6:00,7:00,8:00,9:00,10:00)

I would be thankful if someone could assist me in this regard.

import datetime

a=datetime.datetime.combine(datetime.date.today(), datetime.time(10))

x = [a + datetime.timedelta(hours=i) for i in range(24)]

Upvotes: 0

Views: 456

Answers (3)

陳耀融
陳耀融

Reputation: 476

try this

today = datetime.datetime.today()
x = [ ( (today + datetime.timedelta(hours=i)).hour ) for i in range(24)]
print(x)

each today plus i hour and get their attribute hour

Upvotes: 0

Nir Alfasi
Nir Alfasi

Reputation: 53525

You can modify it a bit:

["{}:00".format((a + datetime.timedelta(hours=i)).hour) for i in range(24)]
                                                   ^

take only the hour from the datetime object and format it the way you want.

OUTPUT

['10:00', '11:00', '12:00', '13:00', '14:00', '15:00', '16:00', '17:00', '18:00', '19:00', '20:00', '21:00', '22:00', '23:00', '0:00', '1:00', '2:00', '3:00', '4:00', '5:00', '6:00', '7:00', '8:00', '9:00']

Upvotes: 0

Mac
Mac

Reputation: 14791

The time() method of the datetime class returns the "time" part of the date/time. Using it, you can achieve what you're after as follows:

times = [dt.time() for dt in x]

Upvotes: 1

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