Reputation: 49
Good day,
I would like to dynamically locate my ticks and showing the min and max of the data (which is varying, thus I really can't harcode the conditions). I'm trying to use matplotlib.ticker functions and the best that I can find is MaxNLocator()
.. but unfortunately, it does not consider the limits of my dataset.
What would be the best approach to my problem?
Thanks!
pseudocode as follows:
import matplotlib.pyplot as plt
from matplotlib.ticker import MaxNLocator
data1 = range(5)
ax1 = plt.subplot(2,1,1)
ax1.plot(data1)
data2 = range(63)
ax2 = plt.subplot(2,1,2)
ax2.plot(data2)
ax1.xaxis.set_major_locator(MaxNLocator(integer=True))
ax2.xaxis.set_major_locator(MaxNLocator(integer=True))
plt.show()
and the output is:
Upvotes: 0
Views: 3090
Reputation: 25370
Not sure about best approach, but one possible way to do this would be to create a list of numbers between your minimum and maximum using numpy.linspace(start, stop, num)
. The third argument passed to this lets you control the number of points generated. You can then round these numbers using a list comprehension, and then set the ticks using ax.set_xticks()
.
Note: This will produce unevenly distributed ticks in some cases, which may be unavoidable in your case
import matplotlib.pyplot as plt
from matplotlib.ticker import MaxNLocator
import numpy as np
data1 = range(5)
ax1 = plt.subplot(2,1,1)
ax1.plot(data1)
data2 = range(63) # max of this is 62, not 63 as in the question
ax2 = plt.subplot(2,1,2)
ax2.plot(data2)
ticks1 = np.linspace(min(data1),max(data1),5)
ticks2 = np.linspace(min(data2),max(data2),5)
int_ticks1 = [round(i) for i in ticks1]
int_ticks2 = [round(i) for i in ticks2]
ax1.set_xticks(int_ticks1)
ax2.set_xticks(int_ticks2)
plt.show()
This gives:
Update: This will give a maximum numbers of ticks of 5, however if the data goes from say range(3)
then the number of ticks will be less. I have updates the creating of int_ticks1
and int_ticks2
so that only unique values will be used to avoid repeated plotting of certain ticks if the range is small
Using the following data
data1 = range(3)
data2 = range(3063)
# below removes any duplicate ticks
int_ticks1 = list(set([int(round(i)) for i in ticks1]))
int_ticks2 = list(set([int(round(i)) for i in ticks2]))
This produces the following figure:
Upvotes: 1