CODEWITHSUNDEEP
pythonstring
user1721105
user1721105

Reputation:

Split a string into a list with parts of N characters in reversed order

I have a string of a fixed length.

>>> s = "000000000001048700000010768"

I need to split this string into parts of 5 characters in reversed order (starting from last character). The output should be:

00 00000 00001 04870 00000 10768

I found the textwrap module, which does the splitting, But the output is slightly different.

>>> import textwrap
>>> print ' '.join(textwrap.wrap(s, 5))
00000 00000 01048 70000 00107 68

Is there an easy solution to do this that I am missing? Maybe to use s.format()

Upvotes: 1

Views: 137

Answers (3)

Neo
Neo

Reputation: 3786

Reverse the string before you split it. 

parts = textwrap.wrap(s[::-1], 5)

Then you can reverse the list, to go back to the original order.

print " ".join(parts[::-1])

Or in short:

print " ".join(textwrap.wrap(s[::-1], 5)[::-1])

Upvotes: 2

Stefan Pochmann
Stefan Pochmann

Reputation: 28606

A regex way, now that you confirmed that you don't actually want to split but just add spaces.

>>> import re
>>> re.sub('(.{5})(?=.)', r'\1 ', s[::-1])[::-1]
'00 00000 00001 04870 00000 10768'

This grabs five chars followed by something (I wish \z would work) and replaces them with themselves plus a space. Reversing the input string beforehand and the output string afterwards in order to do the right-to-left grouping.

Upvotes: 0

user2390182
user2390182

Reputation: 73470

Solution without textwrap and reversing the string twice:

print ' '.join(s[max(i-5, 0):i] for i in reversed(range(len(s), 0, -5)))

Upvotes: 0

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