CODEWITHSUNDEEP
javaandroidlistsortingarraylist
LeTadas
LeTadas

Reputation: 3556

Sorting a List - How to?

I have three object classes called Size1, Size2, Size3

All Size classes has different values (all Values are Strings):

I want to sort a List so that it wouldn't contain duplicate values.

Here it is what I tried:

private List<Size> getSortedSizes(List<Size> allSizes){

  List<Size> sortedArray = new ArrayList<>();

  for (int i = 0; i < allSizes.size(); i++){
    Size size = allSizes.get(i);
    if (sortedArray.size() == 0){
      sortedArray.add(Size);
    } else {
      for (int a = 0; a < sortedArray.size(); a++) {
        if (!sortedArray.get(a).getValue().equals(Size.getValue())) {
          sortedArray.add(Size);
        }
      }
    }
  }
  return sortedArray;
}

Upvotes: 1

Views: 83

Answers (2)

Ibrokhim Kholmatov
Ibrokhim Kholmatov

Reputation: 1089

You could implement your method in the following way:

private Set<Size> getSortedSizes(List<Size> allSizes) {
    Set<Size> sorted = new TreeSet<>(sortedArray);
    return sorted;
}

But you have to implement two methods in your Size class, they are: hashCode() and int compareTo(Object o) from the Comparable interface

Upvotes: 1

OneCricketeer
OneCricketeer

Reputation: 191701

Add to a TreeSet, not an Arraylist

TreeSets are ordered and cannot contain duplicates

Upvotes: 3

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