Reputation: 193
Let's say we have a list of news entries with 7 items.
I've created a pattern with CSS Grid that that should repeat itself after 6 items.
@supports (display: grid)
{
.list
{
display: grid;
grid-gap: 25px;
grid-template-columns: repeat(4, 1fr);
grid-template-rows: auto;
grid-template-areas:
"bigLeft bigLeft right1 right2"
"bigLeft bigLeft bigRight bigRight"
"left1 left2 bigRight bigRight";
}
.item:nth-of-type(6n+1)
{
grid-area: bigLeft;
}
.item:nth-of-type(6n+2)
{
grid-area: right1;
}
.item:nth-of-type(6n+3)
{
grid-area: right2;
}
.item:nth-of-type(6n+4)
{
grid-area: left1;
}
.item:nth-of-type(6n+5)
{
grid-area: left2;
}
.item:nth-of-type(6n+6)
{
grid-area: bigRight;
}
}
desired grid-template-areas
pattern:
Now I want this pattern repeating and repeating the more items added to the list. But HERE you can see as soon as an 7th item is added the pattern will not continued but replaced.
I also tried this with not named areas
.item:nth-of-type(6n+1) {
grid-column: 1 / 3;
grid-row: 1 / 3;
}
.item:nth-of-type(6n+2) {
grid-column: 3 / 4;
grid-row: 1 / 2;
}
.item:nth-of-type(6n+3) {
grid-column: 4 / 5;
grid-row: 1 / 2;
}
.item:nth-of-type(6n+4) {
grid-column: 1 / 2;
grid-row: 3 / 4;
}
.item:nth-of-type(6n+5) {
grid-column: 2 / 3;
grid-row: 3 / 4;
}
.item:nth-of-type(6n+6) {
grid-column: 3 / 5;
grid-row: 2 / 4;
}
But same result...
I don´t find any solutions in the specs to accomplish "repeatable grid-template-areas"
Did anyone of you have an idea?
Upvotes: 18
Views: 20614
Reputation: 6134
You can achieve exactly what you want just in CSS by using explicit column placement and automatic dense row placement:
let list = document.getElementById("list");
for (var i = 1; i <= 100; i++) {
let element = document.createElement("div");
element.className = "item";
element.textContent = i;
list.appendChild(element);
}
@supports (display: grid) {
.list {
width: 80%;
margin: 0 auto;
display: grid;
grid-gap: 25px;
grid-template-columns: repeat(4, 1fr);
grid-template-areas:
"bigLeft bigLeft right1 right2"
"bigLeft bigLeft bigRight bigRight"
"left1 left2 bigRight bigRight";
grid-auto-flow: row dense;
}
.item {
min-height: 200px;
}
.item:nth-of-type(6n + 6),
.item:nth-of-type(6n + 1) {
min-height: 400px;
}
.item:nth-of-type(6n + 1) {
grid-area: auto / bigLeft / span 2;
background: red;
}
.item:nth-of-type(6n + 2) {
grid-area: auto / right1;
background: gray;
}
.item:nth-of-type(6n + 3) {
grid-area: auto / right2;
background: yellow;
}
.item:nth-of-type(6n + 4) {
grid-area: auto / left1;
background: blue;
}
.item:nth-of-type(6n + 5) {
grid-area: auto / left2;
background: lightgray;
}
.item:nth-of-type(6n + 6) {
grid-area: auto / bigRight / span 2;
background: purple;
}
}
<div class="list" id="list">
</div>
The areas are not actually repeating here. The areas are creating implicit named lines, suffixed with -start
and -end
. grid-area: auto / bigLeft / span 2
is shorthand for grid-row: auto / span 2; grid-column: bigLeft
. grid-column: bigLeft
will find the implicit named lines bigLeft-start
and bigLeft-end
and use those for the column start and end. So we are not really using the areas per se. We could just as easily have used line numbers and left out grid-template-areas
altogether.
Now to answer the title of repeating grid-template-areas:
Grid areas cannot repeat but you can repeat named lines and get a similar effect. Repeating rows requires either a fixed number of repeats or a definite height on the grid container which is not really that useful in this case (I am assuming the list has a variable number of items in it).
For example:
let list = document.getElementById("list");
for (var i = 0; i < 60; i++) {
let element = document.createElement("div");
element.className = "item";
element.textContent = i + 1;
let area;
switch (i % 6) {
case 0:
area = "bigLeft";
break;
case 1:
area = "right1";
break;
case 2:
area = "right2";
break;
case 3:
area = "left1";
break;
case 4:
area = "left2";
break;
case 5:
area = "bigRight";
break;
}
let num = Math.floor(i / 6) + 1;
element.style = `grid-row: ${num} ${area}-start / ${num} ${area}-end`;
list.appendChild(element);
}
@supports (display: grid) {
.list {
width: 80%;
margin: 0 auto;
display: grid;
grid-gap: 25px;
grid-template-columns: [bigLeft-start left1-start] 1fr [left1-end left2-start] 1fr [bigLeft-end left2-end right1-start bigRight-start] 1fr [right1-end right2-start] 1fr [right2-end bigRight-end];
grid-template-rows: repeat(10, [bigLeft-start right1-start right2-start] minmax(200px, 1fr) [right1-end right2-end bigRight-start] minmax(200px, 1fr) [bigLeft-end left1-start left2-start] minmax(200px, 1fr) [left1-end left2-end bigRight-end]);
}
.item {
min-height: 200px;
}
.item:nth-of-type(6n+6),
.item:nth-of-type(6n+1) {
min-height: 400px;
}
.item:nth-of-type(6n+1) {
grid-column: bigLeft;
background: red;
}
.item:nth-of-type(6n+2) {
grid-column: right1;
background: gray;
}
.item:nth-of-type(6n+3) {
grid-column: right2;
background: yellow;
}
.item:nth-of-type(6n+4) {
grid-column: left1;
background: blue;
}
.item:nth-of-type(6n+5) {
grid-column: left2;
background: lightgray;
}
.item:nth-of-type(6n+6) {
grid-column: bigRight;
background: purple;
}
}
<div class="list" id="list">
</div>
This shows that named lines can repeat and items can be positioned using the nth named grid line but that has to be done via JavaScript (sadly the counter
function cannot be used here).
The biggest issue with this is that it has a fixed number of repeating rows which is unlikely to be very useful. If we set this to auto-fit
/auto-fill
then it does not work unless the grid container has a definite height
, min-height
, or max-height
.
Upvotes: 2
Reputation: 1
I had the same issue. I just resolved it by repeating the whole 1-row grid with the container and its item in it over and over.
.grid {
display: grid;
grid-template-columns: repeat(4, 1fr);
grid-template-areas:
"item item item item"; /* or whatever is needed */
}
.item {
grid-area: item;
}
<div class="grid">
<div class="item"></div>
</div>
<div class="grid">
<div class="item"></div>
</div>
<div class="grid">
<div class="item"></div>
</div>
....
Upvotes: -1
Reputation: 105893
grid-templates-areas
overides the grid-template-rows
& -columns
. You have to choose, one or the other way to describe your grid layout.
For a repeating pattern, you can use :nth-child(n)
and reset the spanning values : ( https://codepen.io/gc-nomade/pen/qVdpwL ) or snippet below
.grid {
width: 1000px;
margin: 0 auto;
display: grid;
grid-gap: 25px;
grid-template-columns: repeat(4, 1fr);
grid-auto-rows: 200px;
padding: 10px;
counter-reset:div
}
.item:nth-child(6n + 4),
.item:nth-child(6n + 1) {
grid-column: auto /span 2;
grid-row: auto /span 2;
}
.item {
border: solid;
display:flex;
}
.item:before {
counter-increment:div;
content:counter(div);
margin:auto;
font-size:40px;
}
<div class="grid">
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
</div>
if your elements comes randomly but needs to be placed at specific spots in the grid (6th should be at 4th position and spanning) then you will need to set an order value for each of them :( .... there you'll need to relay on javascript if contents and orders may varies
Upvotes: 26