CODEWITHSUNDEEP
javascriptasp.net-mvc-4
shdr
shdr

Reputation: 966

MVC - Send HtmlHelper object by controller Content (function) argument?

Is there a way to return HtmlHelper object from controller to view?

In code:

Controller:

public ActionResult SomeFunc(int id)
    {
        if (condition)
            return Content();//here i would like to send Html.ActionLink("Text", "Action")
        else
            return Content();
    }

The link will get handle in javascript:

        $.get("", { id: $("#id").val() }).
    done(function (data) {
        if (data != 0) {
            $("#someDOMID").val(data);
        }
    });

Upvotes: 2

Views: 271

Answers (2)

Daniel Manta
Daniel Manta

Reputation: 6683

If you only need to send a link as mentioned in your question then try this:

public ActionResult GetLink()
{
    string url = Url.Action("Index", "Home", new { id = 1 });
    return Content(url);
}

Otherwise, it's better to use the Partial View approach.

Upvotes: 1

Ross Bush
Ross Bush

Reputation: 15155

If you want the content to contain a raw html string then you can create a function to render a partial to a string serverside and return that.

You could then take it another step and create a generic ActionLinkPartial that contained one embedded @Html.ActionLink and accepted a model that had your action link configuration settings.

Something like...

   protected string RenderPartialViewToString(string viewName, object model)
    {
        if (string.IsNullOrEmpty(viewName))
            viewName = ControllerContext.RouteData.GetRequiredString("action");

        ViewData.Model = model;

        using (StringWriter sw = new StringWriter())
        {
            ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
            ViewContext viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
            viewResult.View.Render(viewContext, sw);

            return sw.GetStringBuilder().ToString();
        }
    }

And use a model like...

public class ActionLinkModel
{
   public string Text{get;set}
   public string Action{get;set;}
}

Invoke it like...

var html = this.RenderPartialViewToString("Partials/Html/ActionLinkPartial", model);

Upvotes: 2

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