CODEWITHSUNDEEP
iosswiftuitableviewdictionary
Maihan Nijat
Maihan Nijat

Reputation: 9355

How to search for object in Dictionary with SearchBar TableView?

I am using a Dictionary for TableView. I also have a search bar for searching an item in the table.

The data is stored as following:

var namesDic = [String: [Name]]()

And I search through it as:

func updateSearchResults(for searchController: UISearchController) {

    if searchController.searchBar.text! == "" {
        filteredNames = namesDic
    } else {
        filteredNames.removeAll()
        for persons in namesDic {
            let person = persons.value.filter { $0.getName().contains(searchController.searchBar.text!)
            }
            for boy in person {
                filteredNames[String(describing: boy.getName().characters.first!)] = [boy]
            }
        }
    }

    self.tableView.reloadData()
}

Problem: I only get one record now when I search for an item.

Is there a better way to implement above?

Upvotes: 1

Views: 1277

Answers (1)

Maihan Nijat
Maihan Nijat

Reputation: 9355

More lines of code but it is working now. I stored values from dictionary in different variable and filtered those. The filtered values stored in the another variable and then iterate through.

func updateSearchResults(for searchController: UISearchController) {

    if searchController.searchBar.text! == "" {
        filteredNames = namesDic
    } else {
        filteredNames.removeAll()

        var namesArray = [Name]()

        for (_, value) in namesDic {
            namesArray += value
        }

        let namesFilteredArray = namesArray.filter { $0.getName().lowercased().contains(searchController.searchBar.text!.lowercased())
        }

        for filteredName in namesFilteredArray {
            if let letter = filteredName.getName().characters.first {
                if filteredNames[String(letter)] != nil {
                    filteredNames[String(letter)]?.append(filteredName)
                } else {
                    filteredNames[String(letter)] = [filteredName]
                }
            }
        }
    }

    self.tableView.reloadData()
}

Upvotes: 1

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