Reputation: 253
I am trying to wrap a function 'prepared(.)
' from an external library (libpqxx). Said function accepts a variable number of arguments. This is achieved by using multiple operator()
in succession. One operator()
pr. argument, like so:
pqxx::connection connection(connection_str);
connection.prepare("update_person", "UPDATE person SET name = $1 WHERE id = $2 AND version = $3");
pqxx::work w(connection);
// The following executes prepared statement.
// The number of arguments is variable. Notice
// the syntax with multiple () in succession...
w.prepared("update_person")("Jack")(1)(0).exec();
I am trying to wrap the last function by using a variadic template function, like so:
template<typename... T>
pqxx::result exec_prepared(const std::string& name, const T&... args) const {
return w.prepared(name)(args...).exec();
}
...but it does not work. The code compiles, but I get a runtime error saying that the number of arguments do not match the expected number of arguments given the prepared-sql-statement.
Could someone please clarify how wrapping of this type of function is done using variadic template? Thanks!
Upvotes: 2
Views: 372
Reputation: 275800
I would do this with a fold.
template<class F>
struct invoke_by_times_t;
template<class F>
invoke_by_times_t<F> invoke_by_times(F&&)
template<class F>
struct invoke_by_times_t {
F f;
template<class Rhs>
auto operator*(Rhs&&rhs)&&{
return invoke_by_times( std::forward<F>(f)(std::forward<Rhs>(rhs)) );
}
};
which lets us do this:
w.prepared("update_person")("Jack")(1)(0).exec();
with
(invoke_by_times([&](auto&&x){ return w.prepared(x); })*("update_person")*("Jack")*(1)*(0)).f.exec();
now that isn't that useful, but with C++17 that is a simple fold on args!
In c++14, we can write product:
template<class A1, class A2>
delctype(auto) product(A1&& a1, A2&& a2){
return std::forward<A1>(a1)*std::forward<A2>(a2);
}
template<class A1, class A2, class...Args>
delctype(auto) product(A1&& a1, A2&& a2, Args&&...args){
return product(std::forward<A1>(a1)*std::forward<A2>(a2), std::forward<Args>(args)...);
}
giving us:
product(invoke_by_times([&](auto&&x){ return w.prepared(x); }), "update_person", "Jack", 1, 0).f.exec();
Upvotes: 0
Reputation: 66230
Aschepler explained you what's wrong with your actual code.
Not sure to understand how the libpqxx library works but I can try an educated guess and propose a quite simple solution.
What about something like the following code (sorry: untested) ? (and corrected by aschepler; thanks!)
template <typename ... Ts>
pqxx::result exec_prepared (std::string const & name,
Ts const & ... args) const
{
using unused = int[];
auto p = w.prepared(name);
(void)unused { 0, (p = p(args), 0)... };
return p.exec();
}
If you can use C++17, I suppose you can simplify (avoiding the unused trick) as follows (sorry again: not tested)
pqxx::result exec_prepared (std::string const & name,
Ts const & ... args) const
{
auto p = w.prepared(name);
(p = p(args), ...);
return p.exec();
}
Upvotes: 0
Reputation: 72431
If the pack args
represents three parameters, then
return w.prepared(name)(args...).exec();
expands to
return w.prepared(name)(args0, args1, args2).exec();
which is different from the
return w.prepared(name)(args0)(args1)(args2).exec();
which you need.
It looks like you'll need a helper function which recursively applies one argument at a time:
private:
template <typename E>
static E&& apply_prepared_args(E&& expr) {
return std::forward<E>(expr);
}
template <typename E, typename First, typename... Rest>
static decltype(auto) apply_prepared_args(
E&& expr, const First& first, const Rest& ...rest) {
return apply_prepared_args(std::forward<E>(expr)(first), rest...);
}
public:
template<typename... T>
pqxx::result exec_prepared(
const std::string& name, const T&... args) const {
return apply_prepared_args(w.prepared(name), args...).exec();
}
Upvotes: 2