CODEWITHSUNDEEP
if-statementlua
JINEN LIN
JINEN LIN

Reputation: 13

Lua 2nd nested if statement is ignored

I am writing a tic tac toe game for my assignment, and I was stuck with the nested if statement. Attached part of my code below:

if name[1] == "AI" then 
     print("test string")
     playerId = 1
     if level == 1 or level == 2 then
        print("AI lvl 1/2")
        easy()
     elseif level == 3 then
        print("AI lvl 3")
        hard()
     end
elseif name[1] == "player" then
    print("test string2")
    Runtime:addEventListener("touch", fill)
end

while this executed, test string was printed on console, and playerId = 1, but inside 2nd if statement was completely ignored. Not even print on console. Could someone help me solve it please? Or tell me what is wrong with my code. Thanks

Upvotes: 1

Views: 237

Answers (1)

user8816383
user8816383

Reputation:

Add something like print(level, type(level)) to see what level is. Remember, lua can convert strings like '123' to numbers and vice versa when you want to do some arithmetics or string concatenations, but you can't compare strings with numbers like that: 123 == '123' will return false.

So, if level is a string, either replace 1, 2 and 3 in your code with '1', '2' and '3', or convert level to a number: level = tonumber(level)

Upvotes: 3

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