CODEWITHSUNDEEP
phprss
Keiran Lovett
Keiran Lovett

Reputation: 604

PHP RSS based schedule

I have a (probably) simple PHP question. I'm pulling a schedule from an RSS feed. The RSS output looks like such:

17th Jan 2011 : Day 2
18th Jan 2011 : Day 3
19th Jan 2011 : Day 4
20th Jan 2011 : Day 5

I'm trying to remove all the information so only "Day x" remains. The schedule runs on an 8 day cycle, however I am limiting the RSS parser to only one Day so I get the current day.

I'm using this to pull the RSS: 

$rss->parse();
$rss->showStories('1');

After a bit of tinkering I came up with this.

$i=1;
while($i<=8) {
    if (preg_match("/Day 3/i", "Day ".$i)) {
        echo $i;
    } else {
        $i++;
    }
}

Obviously the problem starts here: 

if (preg_match("/Day 3/i", "Day ".$i)) {

I want this to find what the current schedule day is and then display corresponding data. Am I approaching this the right way could someone point me in the right direction please?

Thanks!

EDIT: Fixed code is below for anyone that wants it:

<?php
$url = "";
$rss = simplexml_load_file($url);
if($rss) {
    $items = $rss->channel->item;
        foreach($items as $item) {
            foreach ($item->title as $story) {
                if (!preg_match(date("/jS M Y/"), $story)) continue;
                preg_match("/Day (\d+)/", $story, $m);
                echo $m[1]; // should print "2" if today is January 17
                break; // stop searching
            }
        }
}
?>

Upvotes: 0

Views: 128

Answers (1)

akirk
akirk

Reputation: 6837

You don't say which RSS library you are using, but something along the lines of 

foreach ($rss->stories as $story) {
    // skips stories that are not today
    if (!preg_match(date("/jS M Y/"), $story)) continue;

    preg_match("/Day (\d+)/", $story, $m);
    echo $m[1]; // should print "2" if today is January 17

    break; // stop searching
}

could work. But without any more code it is hard to help further.

Upvotes: 2

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