CODEWITHSUNDEEP
pythonmatplotlibhistogramseabornbins
Jul
Jul

Reputation: 183

Increasing space between bins in seaborn distplot

So I have this, probably, simple question. I created a histogram from data out of an excel file with seaborn. Forbetter visualization, I would like to have some space between the bars/bins. Is that possible?

My code looks as followed

import pandas as pd
import matplotlib as mpl
import matplotlib.pyplot as plt
import numpy as np
import seaborn as sns

%matplotlib inline
from IPython.display import set_matplotlib_formats
set_matplotlib_formats('svg', 'pdf')


df = pd.read_excel('test.xlsx')
sns.set_style("white")
#sns.set_style("dark")
plt.figure(figsize=(12,10))
plt.xlabel('a', fontsize=18)
plt.ylabel('test2', fontsize=18)

plt.title ('tests ^2', fontsize=22)


ax = sns.distplot(st,bins=34, kde=False, hist_kws={'range':(0,1), 'edgecolor':'black', 'alpha':1.0}, axlabel='test1')

A second question though a bit off topic would be, how I get the exponent in the title of the chart to actually be uplifted?

Thanks!

Upvotes: 10

Views: 19257

Answers (3)

miro
miro

Reputation: 780

for Seaborn >= 0.11, use shrink parameter. It scales the width of each bar relative to the binwidth by this parameter. The rest will be empty space.

Documentation: https://seaborn.pydata.org/generated/seaborn.histplot.html

edit: OP was originally asking about sns.distplot(), however, it is deprecated in favor of sns.histplot or sns.displot() in the current version >=0.11. Since OP is generating a histogram, both histplot and displot in hist mode will take shrink

Upvotes: 9

J4FFLE
J4FFLE

Reputation: 182

After posting my answer, I realized I answered the opposite of what was being asked. I found this question while trying to figure out how to remove the space between bars. I almost deleted my answer, but in case anyone else stumbles on this question and is trying to remove the space between bars in seaborn's histplot, I'll leave it for now.

Thanks to @miro for Seaborn's updated documentation, I found that element='step' worked for me. Depending on exactly what you want, element='poly' may be what you are after.

My implementation with 'step':

fig,axs = plt.subplots(4,2,figsize=(10,10))
i,j = 0,0
for col in cols:
    sns.histplot(df[col],ax=axs[i,j],bins=100,element='step')
    axs[i,j].set(title="",ylabel='Frequency',xlabel=labels[col])
    i+=1
    if i == 4: 
        i = 0
        j+=1

enter image description here

My implementation with 'poly':

fig,axs = plt.subplots(4,2,figsize=(10,10))
i,j = 0,0
for col in cols:
    sns.histplot(df[col],ax=axs[i,j],bins=100,element='poly')
    axs[i,j].set(title="",ylabel='Frequency',xlabel=labels[col])
    i+=1
    if i == 4: 
        i = 0
        j+=1

enter image description here

Upvotes: 0

ImportanceOfBeingErnest
ImportanceOfBeingErnest

Reputation: 339230

The matplotlib hist function has an argument rwidth

rwidth : scalar or None, optional
The relative width of the bars as a fraction of the bin width.

You can use this inside the distplot via the hist_kws argument.

import matplotlib.pyplot as plt
import numpy as np
import seaborn as sns

x = np.random.normal(0.5,0.2,1600)

ax = sns.distplot(x,bins=34, kde=False, 
                  hist_kws={"rwidth":0.75,'edgecolor':'black', 'alpha':1.0})

plt.show()

hist_kws

Upvotes: 16

Related Questions