CODEWITHSUNDEEP
gitbash
Tom
Tom

Reputation: 1271

bash separate words in string as indivduled inputs in subshell

I have a function from a file I source that checks if files of interest have a git diff. How do I assigned a value to $patn such that diffs=$(git diff --name-only "$ancestor".."$source_ref" -- "$patn") works as expected? 

build_diff () {
  local patn
  patn=${1:-"."}

  # convert names to hash
  local this_ref
  this_ref=${2:-$(git rev-parse --verify HEAD)}
  local source_ref
  source_ref=$(git show-ref -s --heads "$this_ref" || echo "$this_ref")
  local target_ref
  target_ref=$(git show-ref -s --heads "${3:-master}" || echo "$3")

  # when target and source are the same (post integration), use the branch's
  # parent as ancestor
  # When they are not the same, find the 'best' common node as ancestor
  local ancestor
  if [[ $target_ref == "$source_ref" ]]; then
    ancestor=$(git rev-parse --verify "$target_ref"^)
  else
    ancestor=$(git merge-base --all "$target_ref" "$source_ref" || git merge-base --fork-point "$target_ref" "$source_ref")
  fi

  local diffs
  diffs=$(git diff --name-only "$ancestor".."$source_ref" -- "${patn[@]}")
  echo $diffs
  if [[ -z ${diffs//[[:space:]]/} ]]; then
    echo false
  else
    echo true
  fi
}

-- example function call

FILES=".tool-versions ./other/runner/Dockerfile"
build_diff "$FILES"

If in the script I forget about $1 and patn=( .tool-versions ./other/runner/Dockerfile ) then it works, but I am not able to pass in the list of files via $1

Upvotes: 1

Views: 48

Answers (1)

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798746

You don't. You make $patn an array and then put "${patn[@]}" where you want to use it.

$patn=(foo bar baz)
 ...
echo "${patn[@]}"

Upvotes: 1

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