Reputation: 1509
I have two tables in Postgres:
events (id, occurrence_dates) # occurrence_dates is array
dates_calendar (date)
When events.occurrence_dates
consists of a few equal values, {"2017-11-08 00:00:00","2017-11-08 00:00:00"}
2 values as example, following query gives a single record:
SELECT "events".*
FROM "events"
INNER JOIN dates_calendar dc ON dc.date = ALL(occurrence_dates)
How to get as many records as length of events.occurrence_dates
?
UPD: i'm using Ruby on Rails, but question is provided in SQL context
Rails scope based on @michel.milezzi answer:
scope :all_events, -> do
select("events_sb.*").from(<<-SQL.squish)
dates_calendar dc
INNER JOIN (SELECT *, UNNEST(occurrence_dates) oc_date FROM events) AS events_sb
ON (events_sb.oc_date = dc.date)
SQL
end
Upvotes: 0
Views: 435
Reputation: 11155
You can use UNNEST to expand the array and then use a regular join:
-- CTE with test data
WITH dates_calendar(date) AS (
VALUES
('2017-11-08 00:00:00'::TIMESTAMP),
('2017-11-09 00:00:00'),
('2017-11-10 00:00:00')
), events (id, occurrence_dates) AS (
VALUES
(1, '{"2017-11-08 00:00:00", "2017-11-08 00:00:00","2017-11-09 00:00:00","2017-11-10 00:00:00"}'::TIMESTAMP[]),
(2, '{"2017-11-08 00:00:00","2017-11-09 00:00:00"}'),
(3, '{"2017-11-08 00:00:00"}')
), events_sb AS (
SELECT id, UNNEST(occurrence_dates) oc_date FROM events
)
SELECT
events_sb.*
FROM
dates_calendar dc JOIN events_sb ON (events_sb.oc_date = dc.date) ORDER BY id;
--CTE
WITH events_sb AS (
SELECT id, UNNEST(occurrence_dates) oc_date FROM events
)
SELECT
events_sb.*
FROM
dates_calendar dc JOIN events_sb ON (events_sb.oc_date = dc.date) ORDER BY id;
--SUBQUERY
SELECT
events_sb.*
FROM
dates_calendar dc JOIN (SELECT id, UNNEST(occurrence_dates) oc_date FROM events) AS events_sb ON (events_sb.oc_date = dc.date) ORDER BY id;
To call it in Rails you must do a plain sql, such explained here and here.
Upvotes: 2
Reputation: 724
Is occurrence_dates a json data type? If yes, you could simply use the json_populate_recordset() function.
Upvotes: 0