Reputation: 119
How do I remove null value when there is other non-null value for a specific CaseNumber?
Below is the raw data (Table 1)
CaseNumber | Date
-----------|-----------
A | NULL
A | 08/11/2017
B | 07/11/2017
B | 06/11/2017
C | NULL
C | NULL
D | NULL
F | 05/11/2017
F | NULL
F | 04/11/2017
G | 03/11/2017
G | NULL
Below is the result that I want.
CaseNumber | Date
-----------|-----------
A | 08/11/2017
B | 07/11/2017
B | 06/11/2017
C | NULL
D | NULL
F | 05/11/2017
F | 04/11/2017
G | 03/11/2017
I'm using SQL server 2012.
Upvotes: 1
Views: 508
Reputation: 1561
This was answered in a similar question here.
Easiest way to eliminate NULLs in SELECT DISTINCT?
In your case:
SELECT DISTINCT * FROM Table1
WHERE Date IS NOT NULL OR CaseNumber IN (
SELECT CaseNumber FROM Table1
GROUP BY CaseNumber HAVING MAX(Date) IS NULL)
Upvotes: 3
Reputation: 214957
You might select distinct CaseNumber left join all records where Date is not null:
;with not_null as (
select * from t
where date is not null
), unique_case as (
select distinct casenumber
from t
)
select unique_case.CaseNumber, not_null.Date from unique_case
left outer join not_null
on unique_case.CaseNumber=not_null.CaseNumber
Here is the fiddle with fake data.
Upvotes: 1