Reputation: 27
I was trying to do this work for a class i have but for some reason i can't get the rand()
to work, i've tested several diferent things to try and get it to work, but i just can't figure it out. I'm new to C so i might be doing something wrong here please help.
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
int main() {
srand( time(NULL) );
int num, rep, nu, ba, bas;
char B[20] = "";
char C[20] = "";
printf("Jogo: Converter Bases!\n");
printf("\n Quantas perguntas desejas responder? (1-6)");
scanf("%d", &num);
while (num <= 0 || num > 6) {
printf("\n Introduz um valor valido de 1 a 6: ");
scanf("%d", &num);
}
for (int p=0; p<num; p++) {
nu=rand()% 10;
bas=rand()% 3;
ba=rand()% 3;
printf("\nnu = %i bas = %i ba = %i", &nu, &bas, &ba);
while (ba = bas) {
ba = rand()% 3;
}
if (bas = 0) {
char B[20] = "Octal";
} else if (bas =1) {
char B[20] = "Decimal";
} else {
char B[20] = "Hexadecimal";
}
if (ba = 0) {
char C[20] = "Octal";
} else if (ba =1) {
char C[20] = "Decimal";
} else {
char C[20] = "Hexadecimal";
}
printf("Converte %i de base %c para base %c\n", &nu, &B, &C);
scanf("%d", &rep);
}
return 0;
}
`
Upvotes: 0
Views: 65
Reputation: 107042
It's because you're writing:
printf("%d", &x);
When you should be writing
printf("%d", x);
In the first case you're printing the memory address of the variable; in the second - the contents of the variable.
The &
is required for scanf
, because it needs to know the memory address where to put the results, but printf only needs the value.
Upvotes: 4